Answer:
x = 3, y = 1 is the solution of the given system.
Step-by-step explanation:
Here, the given system of equations is:
y = -x + 4 ...... (1)
y = x - 2 .......... (2)
Now, to find the solution of the system, SUBSTITUTE the value of y from equation (1) in to the equation (2). We get ,
y = x - 2 ⇒ -x + 4 = x - 2 ( as from (1), y = -x + 4)
or, -x -x = -2 -4
or, - 2 x = -6 ⇒ x = 6/2 = 3
or, x = 3
⇒ y = x - 2 = 3 - 2 = 1
⇒ y = 1
Hence, x = 3, y = 1 is the solution of the given system.
4 as the denominator of the fraction is equal to the degree of the root so the answer is the 4th root of x
![\sqrt[4]{x}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bx%7D%20)
Let's multiply out the equation 6x+2 times 6x+2 using the square. Draw a 2 by 2 bow and put the equation across the bottom and verically. Multiply across to get this. 6x times 6x =36x^2 6x times two =12x do it again and get 12x. 2*2=4. That means x would equal 24.
Answer:
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Step-by-step explanation:
