Answer:
B) x = 2, y = 1
Step-by-step explanation:
Add the two equations to eliminate the x-variable.
(x +3y) +(-x +6y) = (5) +(4)
9y = 9 . . . . . . .simplify
y = 1 . . . . . . . . divide by 9
You can substitute this value into either equation to find x.
x + 3(1) = 5
x = 2 . . . . . . . . subtract 3
The solution is (x, y) = (2, 1).
Let us say, the CD amount she invested is "c"
and the amount she invested in the savings bond is "s"
she invested a total of 5,000
so, whatever "c" is and "s" is, c + s = 5,000
now, the CD account earned 4% in interest
4% in decimal form is 4/100 or 0.04
she also earns 7% from the saving bonds,
7/100 is 0.07
the interest earned after one year are 300
that is, the 4% per year and the 7% per year add up to 300 bucks
so, one can say that
0.04c + 0.07s = 300
Answer:
a) Only the first one is an identity.
Step-by-step explanation:
1). 8 cos O tan O csc O = 8 simplifies to:
cos O tan O csc O = 1
cos O * (sin O / cos O) * (1 /sin O)
= cos O sin O / cos O sin O
= 1
So it is identity.
2) 13 sec^2 O/ cos^2 O - tan^2 O / cos^2O
= 13 sec^2 O - tan^2 O / cos^2 O
Now sec^2 O = 1 + tan^2 O, so we have:
(13( 1 + tan^2 O) - tan^2 O) / cos^2 O
= (12 tan^2 O + 13) / cos^2 O
This is not always = 2 so its not an identity.
I’m assuming you’re trying to find the equation of a line that intersects the point. In order to do this you need to plug in your points into the equation that at the moment just has your slope.
y=5x —> 13=5(3)+b —> 13=15+b —> 13-15=b
—> b=-2
Now that you finally found your b (y-intercept) you can just plug it in!
y=5x-2