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uysha [10]
3 years ago
7

Which multimedia sources are best for a student writing a research paper on childhood obesity? Check all that apply.

Mathematics
2 answers:
seropon [69]3 years ago
7 0

Answer:

The answer is 1&2  

Step-by-step explanation:

1.) and documentary is one of the best resource if you have nothing. but if all else fails talk to a doctor they will help you.

Hope this helps :) :) :) :)

11111nata11111 [884]3 years ago
5 0

Answer:

1,2, and 5

Step-by-step explanation:

these are all credible and relate to they key topic otherwise known as the main idea

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Can someone please help me on the second on please thanks:)
eimsori [14]
Since she spent $9.72 and deposited $9.72 her bank balance did not change at all. She basically paid off how much she spent on lunch on Wednesday.
7 0
3 years ago
Read 2 more answers
If if the branding division were to experience the same percentage increase from year 2 to year 3 as they did from year 1 to yea
Sedaia [141]
Since the basis is from year 1 to year 2, calculate first for the difference of their percentages. That would be:

Difference = year 2 - year 1
Difference = 2.32% - 1.1% = 1.22%

We apply this same value of percentage increase from year 2 to year. Thus, the percentage for year 3 is:

% Year 3 = % Year 2 + percentage increase
% Year 3 = 2.32% + 1.22%
% Year 3 = 3.54%
6 0
3 years ago
Find a unit vector that has the same direction as the vector a and the opposite direction of the vector
nasty-shy [4]
The unit vector is given by the following formula:
 a '= (a) / (lal)
 Where,
 a: vector a
 lal: Vector module a
 We are looking for the module:
 lal = root ((- 15) ^ 2 + (8) ^ 2)
 lal = 17
 Same direction:
 a = -15i + 8j
 The unit vector is:
 a '= (1/17) * (- 15i + 8j)
 Opposite direction:
 a = 15i - 8j
 The unit vector is:
 a '= (1/17) * (15i - 8j)
 Answer:
 
a unit vector that has the same direction as the vector a is:
 
a '= (1/17) * (- 15i + 8j)
 
a unit vector that has the opposite direction of the vector a is:
 
a '= (1/17) * (15i - 8j)
5 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
3 years ago
Evaluate. 10/1·(−4) Enter your answer in the box.
Marrrta [24]

Step-by-step explanation:

10/1(-4)

10(-4)

=-2.5 or 5/-2

4 0
2 years ago
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