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Bogdan [553]
2 years ago
10

What is 5X9 please help

Mathematics
2 answers:
pogonyaev2 years ago
7 0
5x9 is the answer 45
Cerrena [4.2K]2 years ago
6 0
The answer to this question is 45
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What is the solution of this proportion 4/9 = 6/d
Alchen [17]

Answer:

d = 2/27

Remember that when a variable is times with a number you <u>divide</u> the number on both sides.

When a variable is divided by a number, you <u>multiply</u> the number on both sides.

Hope this helps you and thank you !!

4 0
3 years ago
find the equation of a line that is parallel to the straight line 2x-y=-3 and crosses the x-axis at x=-5​
Alecsey [184]

Answer:

y=2x+10

Step-by-step explanation:

In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.

In this case it is y=2x+3

All parallel lines have the same gradient. The gradient of this line = 2.

If the line crosses the x axis at x=-5, then when x =-5 y = 0.

If you put all this in the form y =ax + b you get 0 = 2(-5) +b

So all you need to do to find b is rearrange. b = 10.

Therefore your line has gradient 2 and y intercept 10.

y = 2x + 10

7 0
3 years ago
Students at a sports college choose activities for games.
Mila [183]

Answer:   48 students

Step-by-step explanation:   1+4=5

60÷5=12

12x4=48

7 0
1 year ago
Read 2 more answers
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

7 0
3 years ago
A surveyor, Toby, measures the distance between two landmarks and the point where he stands. He also measured the angles between
vagabundo [1.1K]
What we know so far:
Side 1 = 55m
Side 2 = 65m
Angle 1 = 40°
Angle 2 = 30°

What we are looking for:
Toby's Angle = ?
The distance x = ?

We need to look for Toby's angle so that we can solve for the distance x by assuming that the whole figure is a SAS (Side Angle Side) triangle.

Solving for Toby's Angle:
We know for a fact that the sum of all the angles of a triangle is 180°; therefore,
180° - (Side 1 + Side 2) = Toby's Angle
Toby's Angle  = 180° - (40° + 30°)
Toby's Angle = 110°

Since we already have Toby's angle, we can now solve for the distance x by using the law of cosines r² = p²+ q²<span>− 2pq cos R where r is x, p is Side1, q is Side2, and R is Toby's Angle.
</span>
x² = Side1² + Side2² - 2[(Side1)(Side2)] cos(Toby's Angle)
x² = 55² + 65² - 2[(55)(65)] cos(110°)
x² = 3025 + 4225 -7150[cos(110°)]
x² = 7250 - 2445.44
x = √4804.56
x = 69.31m

∴The distance, x, between two landmarks is 69.31m
8 0
3 years ago
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