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DaniilM [7]
4 years ago
8

Which of the following is the solution to the inequality below? 2x−4≤12

Mathematics
2 answers:
Afina-wow [57]4 years ago
8 0

Answer:

x   ≤ 8

Step-by-step explanation:

Given

2x - 4 ≤ 12

Isolate the term in x by adding 4 to both sides

2x ≤ 16 ( divide both sides by 2 )

x ≤ 8 ← is the solution

Aneli [31]4 years ago
4 0

Answer:

x= <8

hope this helps

Step-by-step explanation:

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3 years ago
Can someone help me out with this? I’m not sure what I’m doing wrong.
Nadusha1986 [10]

Answer:


Step-by-step explanation:

This is a system of inequalities such that:

\left \{ {{2x+3y\geq 2} \atop {3x-4y\leq 3}} \right.

Let's start by solving for y for both equations:

Equation 1:

2x+3y\geq  2\\\\3y\geq -2x+2\\\\y \geq \frac{-2x+2}{3}

Equation 2:

3x-4y\leq 3\\\\-4y\leq -3x+3\\\\y\geq -\frac{(-3x+3)}{4}


Now if we substitute the 2nd y into the first equation we obtain:

2x+3(\frac{3x-3}{4}) \geq  2\\\\2x+\frac{9x-9}{4}\geq 2\\\\\frac{8x+9x-9}{4}\geq 2\\\\17x-9\geq 8\\\\17x\geq 17\\\\x\geq 1


Now we will solve for the second equation using the first result of y and we obtain:

3x-4(\frac{-2x+2}{3}\leq 3\\\\3x+\frac{8x-8}{3}\leq 3\\\\\frac{9x+8x-8}{3}\leq 3\\\\17x-8\leq 9\\\\17x\leq 17\\\\x\leq 1

And so our solution for the system of equations is:

x \leq 1\\and \\y\geq \frac{-2x+2}{3}

As well as:

x>1\\and\\y\geq \frac{3x-3}{4}


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