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Phantasy [73]
3 years ago
14

Rewrite the fraction in the sentence below as a percentage.

Mathematics
1 answer:
Furkat [3]3 years ago
6 0

Answer:

55%

Step-by-step explanation:

Total number of targets = 20

Number of targets hit = 11

100 / 20 = 5

5 * 11 = 55

This means that 55% of the targets were hit.

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29 If we round to 1 significant figure, sound travels at a speed of approximately 0.3 kilometers per second, while light travels
MrRissso [65]

Answer:

3 x 10^-1 km per second.

Step-by-step explanation:

A scientific notation includes c x 10^n. c is a number between 1-9, and n is the nth power of 10.

If we move the decimal in 0.3 to the right by 1 place, we can get "c", which will be 3. Since we have moved the decimal to the right, each place moved right counts as -1 for n.

So, the answer is 3 x 10^-1 km per second.

7 0
3 years ago
(−7x 2 −4)+(−7x 2 −6x−2)
seropon [69]

-20

Explanation:

( − 7   ^ 2  −  4 )  +  ( − 7   ^ 2  −  6  − 2 )

Eliminate the redundant parentheses, subtract the numbers which will get you, combine like terms, rearrange terms, then your solution is:

− 1 4 2 −6 −6

Figure that problem out then you will get -20.

8 0
3 years ago
Read 2 more answers
A racing car used 255 litres of fuel to complete a 340 km race.
Kisachek [45]
The answer is 151 km.
4 0
3 years ago
Read 2 more answers
Find the solution for the question.<br> X - 4)(x + 3) = 0
DiKsa [7]

Step-by-step explanation:

The answer is 0 because all you have to do is calculate

5 0
3 years ago
Eduardo and Sarawong are selling wrapping paper for a school fundraiser. Eduardo sold 5 rolls of plain wrapping paper and 5 roll
Digiron [165]

Answer: A roll of plain wrapping paper costs $17, while a roll of holiday wrapping paper costs $20.

Step-by-step explanation: First let us represent a roll of plain wrapping paper with letter p and a roll of holiday wrapping paper would be represented by d. If Eduardo sold 5 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $185, then we can express this as

5p+ 5d= 185

Also if Sarawong sold 14 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $338, then this too can be expressed as

14p + 5d = 338

Now we have a pair of simultaneous equations which are,

5p + 5d = 185 ———(1)

14p + 5d = 338 ———(2)

Since all the variables have coefficients greater than 1, we shall use the elimination method. Note that the coefficients of the d variable are both 5, so straight away we subtract equation (1) from equation (2) and we now have;

(14p - 5p) + (5d - 5d) = 338 - 185

9p = 153

Divide both sides of the equation by 9

p = 17

Having calculated p, we can now substitute for the value of p into equation (1)

5p + 5d = 185

5(17) + 5d = 185

85 + 5d = 185

Subtract 85 from both sides of the equation

5d = 100

Divide both sides of the equation by 5

d = 20

Hence, the cost per roll of plain wrapping paper is $17, while the cost per roll of holiday wrapping paper is $20.

5 0
3 years ago
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