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grigory [225]
3 years ago
8

M2 -5m - 24 pls answer my questions​

Mathematics
1 answer:
Gwar [14]3 years ago
7 0

Answer:

(m+3) (m-8)

Step-by-step explanation:

...,...............

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Which is the best estimate for the height of the candle after 1 hour?
salantis [7]

Answer:

about 5.5

Step-by-step explanation:

so 5cm. Just trust me i dont know how to explain but i know its right.

7 0
3 years ago
PLEASE HELP ME AND BE CORRECT BEFORE ANSWERING
ddd [48]

Answer:

8 units left , 5 units up

Step-by-step explanation:

4 0
3 years ago
Your local grocery store is having a
galina1969 [7]

Answer:

You should buy a 12-pack of 12 oz cans for $4.75 rather than seven 20 oz bottles that are on sale for $0.90 because seven 20 oz bottles that are on sale for $0.90 cost $6.30 all together which means  a 12-pack of 12 oz cans for $4.75 is cheaper than seven 20 oz bottles that are on sale for $0.90.

5 0
3 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
The masses mi are located at the points pi. find the moments mx and my and the center of mass of the system. m1 = 2, m2 = 5, m3
creativ13 [48]
Most graphing calculators will do weighted averages pretty easily. It is mostly a matter of data entry.

mx = -2
my = 10
(x, y) = (mx, my)/10 = (-0.2, 1)

6 0
4 years ago
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