Let's say that the value invested in the account with a rate of 8% is "x", then the amount invested in the account with a rate of 12% is:
To calculate the total interest we need to calculate the interest of each individual account and sum them:
The total interest is the sum of the two expressions above:
The value invested in the account with 8% interest is 830, the one invested in the account with 12% interest is 1280.
Y should also be halved.
For example, if x=4 and y=2, x=2y.
If x is halved for x=2, you get 2=2y, or y=1, which is still one half of x, so the proportion remains the same.
Answer:
C. 3x
Step-by-step explanation:
The first two choices give 1 solution each.
The last choice gives an infinite number of solutions.
Choice C. gives no solution.
3x + 9 = 3x
Subtract 3x from both sides.
9 = 0
Since 9 = 0 is false, equation 3x + 9 = 3x has no solution.
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = £600
r = 3.2% = 3.2/100 = 0.32
n = 1 because it was compounded once in a year.
t = 6 years
Therefore,.
A = 600(1 + 0.032/1)^1 × 6
A = 600(1.032)^6
A = £724.82
