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Lyrx [107]
2 years ago
15

A bicycle manufacturer uses the given expression to model the monthly profit from sales of a new model of bicycle, where x is th

e selling price of one bicycle, in dollars. At what selling prices for the bicycle will the manufacturer make neither a profit nor a loss?
Mathematics
1 answer:
forsale [732]2 years ago
8 0

Answer:

The manufacturer will have no profit or loss when the selling price equals $200 or $100.

Step-by-step explanation:

The expression to model the monthly profit from sales of a new model of bicycle is

-x^2 + 300x -20,000

Let

f(x) -----> the monthly profit in dollars

x -----> s the selling price of one bicycle in dollars

f(x)= -x^{2}+300x-20,000

we know that

The manufacturer will make no profit nor a loss when the profit is equal to zero

so

f(x)=0

-x^{2}+300x-20,000=0

Multiply by -1 both sides

x^{2}-300x+20,000=0

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

a=1\\b=-300\\c=20,000

substitute in the formula

x=\frac{300(+/-)\sqrt{-300^{2}-4(1)(20,000)}}{2(1)}

x=\frac{300(+/-)\sqrt{10,000}}{2}

x=\frac{300(+/-)100}{2}

x=\frac{300(+)100}{2}=200

x=\frac{300(-)100}{2}=100

therefore

The manufacturer will have no profit or loss when the selling price equals $200 or $100.

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Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ < 98.6, and level of significance α = 0.05. 98 99.6 97.8
andrezito [222]

Answer:

The t-score is -1.8432    

Step-by-step explanation:

We are given the following in the question:  

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1964.4}{20} = 98.22

Sum of squares of differences = 16.152

s = \sqrt{\dfrac{16.152}{49}} = 0.922

Population mean, μ = 98.6

Sample mean, \bar{x} = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

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Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432

The t-score is -1.8432    

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Answer:

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Step-by-step explanation:

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