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vova2212 [387]
3 years ago
5

3m + 1 greater than or equal to 7

Mathematics
1 answer:
Veronika [31]3 years ago
4 0
Greater than











i did this
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The function d(s) = 0.0056s squared + 0.14s models the stopping distance
victus00 [196]

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be d(s) = 0.0056\cdot s^{2} + 0.14\cdot s, where d is the stopping distance measured in metres and s is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of d(s).

2) Add the function d = 7\,m.

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

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3 years ago
Line XY bisects and is perpendicular to AB and CD. CD = 10 and XY = 24. What is the length of AP?
myrzilka [38]

Answer:

<u>AP = 13</u>

Step-by-step explanation:

See the attached figure.

CD = 10 and XY = 24

Line XY bisects and is perpendicular to AB and CD

∴ XY bisects at Y

∴ CY = 0.5 CD = 0.5 * 10 = 5

And from the geometry of the shape

P is the midpoint of XY

∴ XP = YP = 0.5 XY = 0.5 * 24 = 12

XY is perpendicular to CD

∴ ΔPYC is a right triangle at Y

∴ PC (hypotenuse) = \sqrt{PY^2+YC^2} =\sqrt{12^2+5^2}=\sqrt{144+25} =\sqrt{169} =13

From the figure AP = PC = 13

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Step-by-step explanation:

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