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oee [108]
3 years ago
14

A jar contains 16 quarters, 6 dimes ,7 nickels and 11 pennies, if one coin is selected at random, what is the probability it is

worth more than 5 cents
Mathematics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

11/20

Step-by-step explanation:

5 cents is worth $0.05.

A quarter is worth $0.25.

A dime is worth $0.10

A nickel is worth $0.05

A penny is worth $0.01

In total there are 40 coins in the jar.

The coins that are worth more than $0.05 dollars are the dimes and quarters, so there are 22 coins worth more than $0.05.

Therefore, the probability of of picking a coin worth more than 5 cents is:

22 / 40 = 11/20

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2 years ago
Use the rational zero theorem to create a list of all possible rational zeroes of the function f(x) = 14x^7 - 4x^2 + 2
Bas_tet [7]

f(x) = 14x^7 - 4x^2 + 2

Use the rational zero theorem

In rational zero theorem, the rational zeros of the form +-p/q

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In our f(x), constant is 2 and leading coefficient is 14

Factors of 2  are 1, 2

Factors of 14  are 1,2, 7, 14

Rational zeros of the form +-p/q  are

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Now we separate the factors

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+-1, +-\frac{1}{2}, +-\frac{1}{7}, +-\frac{1}{14},+-2, +-1 , +-\frac{2}{7}, +-\frac{1}{2}

We ignore the zeros that are repeating

+-1, +-2, +-\frac{1}{2}, +-\frac{1}{7}, +-\frac{1}{14}, +-\frac{2}{7}

Option A is correct


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