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Svet_ta [14]
3 years ago
13

Which shows this price as a correct unit price? $3.60 for 4 watermelons.

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0

Answer:

$0.90

Step-by-step explanation:

You are solving for the price of one watermelon (a unit of watermelon).

What is given to you is the price of 4 watermelons, or $3.60. To solve, simply divide $3.60 with 4:

3.60/4 = 0.90

$0.90 is your answer.

Remember to add the hundredth place value (0), as money goes to the hundredth place value.

~

Kisachek [45]3 years ago
3 0

Answer: 90 cents

Step-by-step explanation: Unit price means the cost per unit, in this case the cost per watermelon. Since we know that it costs $3.60 for 4 watermelons, to find the cost  for 1 watermelon, we need to divide 4 into $3.60 or 4 into 3.60.

4 divides into 36 9 times and 9 x 4 is 36 so we put 36 and the 36 and subtract. Finally, we bring up the decimal point and put a zero in front of it to get 0.9 which means that each watermelon cost 90 cents.

So the unit price is 90 cents per watermelon.

I attached my long division in the image provided.

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Is this correct? if not what is the answer
LenaWriter [7]

Answer:

x = 50

Step-by-step explanation:

You are correct.

x + m<PQS + m<PSQ = 180

m<PQS = m<QRT = 70

m<QST + m<PSQ = 180

120 + m<PSQ = 180

m<PSQ = 60

x + 70 + 60 = 180

x + 130 = 180

x = 50

Great job!

4 0
3 years ago
Simplify by combining like terms <br><br> 7/2x-8.62-3/2x-2.38
Dimas [21]
Like terms are terms whose variables are the same.
7/2 x and -3/2x have the same variable, so we can combine them to make 4/2x.
-2.38 and -8.62 are both integers, so we can combine them to make -11.
This gives us -11 + 4/2x.
This is your final answer.
5 0
3 years ago
Please help. I can't figure out answer.
IgorC [24]
Answer four hundred and twenty
8 0
4 years ago
Helpppppppp ASAPPPP PLZZZZZZ
juin [17]
What do you need help with?
6 0
3 years ago
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
3 years ago
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