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2 years ago

6

If it is about 240 miles to the international space station, how many kilometers is 240 miles? Round your answer to the nearest

whole kilometer.

2 answers:

Gemiola [76]2 years ago

4 0

Answer:

240: The average distance in miles above Earth's surface the ISS orbits (400 kilometers). On a clear ... 8: The total length, in miles, of wire that connects the electrical power system (12.9 km).

Step-by-step explanation:

have a nice day ahead hope it will help you

Deffense [45]2 years ago

3 0

Answer:

386.243

Step-by-step explanation:

386.243 is rounded to 386

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What is the prime factor of 236

grin007 [14]

Answer:

Step-by-step explanation:

prime factorization calculator of 326

Positive Integer factors of 326 = 2, 163, 326 divided by 2, 163, gives no remainder. They are integers and prime numbers of 326, they are also called composite number.

326 is a composite number.

Prime factorization: 326 = 2 x 163.

The exponents in the prime factorization are 1 and 1. ...

Factors of 326: 1, 2, 163, 326.

Factor pairs: 326 = 1 x 326 or 2 x 163.

326 has no square factors that allow its square root to be simplified.

8 0

3 years ago

In a park,a sidewalk is built around the edge of a circular pond.The sidewalk is 7 feet wide,and the pond measure 15 feet across

densk [106]

Answer:

91.14 feet

Step-by-step explanation:

Given:

In a park,a sidewalk is built around the edge of a circular pond.

The sidewalk is 7 feet wide, and the pond measure 15 feet across.

Question asked:

What amount of railing would be needed to go completely around the outer edge of the sidewalk?

Solution:

From distance from one edge of the pond to the another = 15 feet

That means diameter of the pond = 15 feet

And width of the sidewalk = 7 feet all around

combined diameter = 15 + 7 + 7 = 29 feet

Radius,r = $\frac{Diameter}{2} =\frac{29}{2} ==14.5\ feet$

That means distance between outer edge of the sidewalk to the center of the circular pond = 14.5 feet

Now, we will have to find circumference of outer circular edge of sidewalk:

$Circumference\ of\ circle=2\pi r$

$=2\times\frac{22}{7} \times14.5\\ \\ =\frac{638}{7} \\ \\ =91.14\ feet$

Therefore, 91.14 feet would be needed to go around the outer edge of the sidewalk.

7 0

3 years ago

What is -12(5x+2x) Distributed

Mashcka [7]

Answer:

Step-by-step explanation:

=-84x

Hope it helps

Mark me as brainiest

4 0

3 years ago

Read 2 more answers

The skoblickis are building a new home. The scale drawing below shows their master bedroom. Find the length and width of the act

jolli1 [7]

Answer:

Length: 20

Width:15

Step-by-step explanation:

Hope this Helps!

3 0

2 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago