Answer:
Step-by-step explanation:
7/12
1)7*2/12*2 = 14/24
2) 7*3 / 12*3 = 21/36
3) 7*4/12*4 = 28/48
Answer:
z (min) = 705
x₁ = 10
x₂ = 9
Step-by-step explanation:
Let´s call x₁ quantity of food I ( in ou ) and x₂ quantity of food II ( in ou)
units of vit. C units of vit.E Cholesterol by ou
x₁ 32 9 48
x₂ 16 18 25
Objective function z
z = 48*x₁ + 25*x₂ To minimize
Subject to:
1.-Total units of vit. C at least 464
32*x₁ + 16*x₂ ≥ 464
2.- Total units of vit. E at least 252
9*x₁ + 18*x₂ ≥ 252
3.- Quantity of ou per day
x₁ + x₂ ≤ 35
General constraints x₁ ≥ 0 x₂ ≥ 0
Using the on-line simplex method solver (AtoZmaths) and after three iterations the solution is:
z (min) = 705
x₁ = 10
x₂ = 9
Answer:
Step-by-step explanation:
Answer:
0.2231 (22.31%)
Step-by-step explanation:
defining the event F = the marketing company is fired, then the probability of being fired is:
P(F)= probability that the advertising campaign is cancelled before lunch * probability that marking department is fired given that the advertising campaign was cancelled before lunch + probability that the advertising campaign is launched but cancelled early * probability that marking department is fired given that the advertising campaign is launched but cancelled early .... (for all the 4 posible scenarios where the marketing department is fired)
thus
P(F) =0.10 * 0.74 + 0.18 * 0.43 + 0.43 * 0.16 + 0.29*0.01 = 0.2231 (22.31%)
then the probability that the marketing department is fired is 0.2231 (22.31%)
Part A: c for cost. c=0.31m+0.5
0.31m is the cost per minute. 0.5 is cost per call.
Part B: 0.31m+0.5=5.15 to solve we must rearrange.
subtract 0.5 from each side giving us 0.31m=4.85
divide by 0.31 giving us m=15.65
