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PilotLPTM [1.2K]
3 years ago
6

He coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) .

Mathematics
2 answers:
sasho [114]3 years ago
6 0

Answer:

reflection across the y-axis and translation 2 units right.

Step-by-step explanation:

miv72 [106K]3 years ago
5 0
Given that th<span>e coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) and the coordinates of the vertices of △D′E′F′ are D′(0, −1) , E′(−5, −1) , and F′(0, −3) .

Notice that the y-coordinates of the pre-image and that of the image are the same, which means that there is a reflection across the y-axis.

A refrection across the y-axis results in the change in sign of the x-coordinates of the pre-image and the image while the y-coordinate of the image remains the same as that of the pre-image.

A refrection across the y-axis of </span>△DEF with vertices D(2, −1) , E(7, −1) , and F(2, −3) will result in and image with vertices (-2, -1), (-7, -1) and (-2, -3) respectively.

Notice that the x-coordinate of the final image △D′E′F′ with vertices <span>D′(0, −1) , E′(−5, −1) , and F′(0, −3) is 2 units greater than the vertices of the result of recting the pre-image across the y-axis.

This means that the result of refrecting the pre-image was shifted two places to the right.

Therefore, </span>the sequence of transformations that maps △DEF to △D′E′F′ are reflection across the y-axis and translation 2 units right.
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