Answer:
A.If the value of b is increased from 0, the graph moves up.
Step-by-step explanation:
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²
Hey there!
Tim drives 300 kilometers.
Work: 80 x 3 = 240
Then, 45 minutes is 3/4 of an hour, so if you were to do 3/4 of 80 it is 60
Now, add 240 + 60 = 300
Hope I was able to help!
Answer:
5.48
Step-by-step explanation:
add 2.98 1.75 and 0m75
The given function is

with
t = time, hours
f = temperature, °C
Because the maximum and minimum values for the Sine function are +1 and -1 respectively,
The maximum value of f = 33 - 20 = 13.
The minimum value of f = -33 - 20 = -53.
The period, T, is given by

Answer:
Maximum: 13°; Minimum: -53°; period: 4 hours