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Vesna [10]
3 years ago
7

Graph y=-2x+5y=−2x+5y, equals, minus, 2, x, plus, 5.

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

Please check the graph of the function y=-2x+5 attached below.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the function

y=-2x+5

comparing with the slope-intercept form of the line equation

The slope m = -2

The y-intercept b = 5

The graph of y=-2x+5 is attached below.

<u>Determining the y-intercept from the graph</u>

We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

From the graph, it is clear

at x = 0, y = 5

Thus, the y-intercept b = 5

Please check the graph of the function y=-2x+5 attached below.

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3 years ago
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Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of
leonid [27]

Answer:

\frac{3}{13} + \frac{2i}{13}

Step-by-step explanation:

The multiplicative inverse of a complex number y  is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = \frac{1}{3-2i}

We have that

(3- 2i)\frac{1}{3-2i} = 1 would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}

Thus, the multiplicative inverse would be \frac{3}{13} + \frac{2i}{13}

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13}  =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1

Thus, the number we found is indeed the multiplicative inverse of  3 - 2i

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Answer:

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