Answer:
if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero
Explanation:
The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes
I = I₀ cos² θ
therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero
Take more data. random errors can be evaluted through statistical analysis and can be reduce by average over a large number of observations. this is all i know im in middle school hope this help
Answer is B. Since the number in the inequality is 5, we must be able to include it in the inequality, and therefore must use an “equal to” inequality. Since there are values less than 5, we must be able to include those numbers in the inequality. A greater than sign would therefore not make sense, meaning you must use a less than sign. Combine these two observations and you will find that the graph must be less than or equal to 5.
Answer: The current is 11 Amperes
Explanation:
Answer:
The value is ![E_t = 17958.2 \ J](https://tex.z-dn.net/?f=E_t%20%3D%2017958.2%20%5C%20%20J)
Explanation:
From the question we are told that
The atmospheric temperature is
The molar mass of carbon dioxide is
The pressure is ![P = 92 \ atm =](https://tex.z-dn.net/?f=P%20%3D%20%2092%20%5C%20%20atm%20%20%3D)
The number of moles is
Generally the translational kinetic energy is mathematically represented as
![E_t = \frac{f}{2} * n * R T](https://tex.z-dn.net/?f=E_t%20%3D%20%20%5Cfrac%7Bf%7D%7B2%7D%20%2A%20%20n%20%20%2A%20%20R%20T)
Here R is the gas constant with value ![R = 8.314 J\cdot K^{-1}\cdot mol^{-1}](https://tex.z-dn.net/?f=R%20%20%3D%20%208.314%20J%5Ccdot%20K%5E%7B-1%7D%5Ccdot%20mol%5E%7B-1%7D)
Generally the degree of freedom of carbon dioxide in terms of translational motion is f = 3
So
![E_t = \frac{ 3}{2} * 2 * 8.314 * 720](https://tex.z-dn.net/?f=E_t%20%3D%20%20%5Cfrac%7B%203%7D%7B2%7D%20%2A%20%20%202%20%20%20%2A%20%20%208.314%20%2A%20%20720)
=> ![E_t = 17958.2 \ J](https://tex.z-dn.net/?f=E_t%20%3D%2017958.2%20%5C%20%20J)