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Anettt [7]
3 years ago
12

What percentage of the intensity gets through both polarizers?

Physics
1 answer:
sp2606 [1]3 years ago
8 0

Answer:

if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

Explanation:

The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes

                I = I₀ cos² θ

therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

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A ski resort consists of a few chairlifts and several interconnected downhill runs on the side of a mountain, with a lodge at th
Aleks04 [339]
  1. A sketch of the junction between one chairlift and two runs is shown in the image attached below.
  2. For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

<h3>What is Kirchhoff's loop rule?</h3>

Kirchhoff's loop rule is also referred to as Kirchhoff's second law or Kirchhoff's voltage law, and it states that the algebraic sum of all the electric potential differences around any closed loop is equal to zero.

<h3>How to connect two runs in series?</h3>

Since the chairlifts are analogous to batteries, and the runs are analogous to resistors, the two runs would represent resistors that are connected in series with the lift, which represents the battery. Similarly, these three runs can also be connected in parallel by altering the positions of the runs with the battery.

For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

Read more on Kirchhoff's loop rule here: brainly.com/question/15003023

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7 0
1 year ago
Two thousand two hundred frequent business travelers are asked which midwestern city they prefer: Indianapolis, Saint Louis, Chi
drek231 [11]
Frequency Table
City                       Frequency
Indianapolis              124
Saint Louis                416
Chicago                  1,225
Milwaukee                 435

Relative Frequency Table
City                            Relative Frequency
Indianapolis              124/2200 = 31/550
Saint Louis                416/2200 = 52/275
Chicago                  1,225/2200 = 49/88
Milwaukee                 435/2200 = 87/440
5 0
3 years ago
Planets beyond the solar system.On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital dista
Evgesh-ka [11]

Answer:

Part a)

M = 2.31 \times 10^{30} kg

Part b)

M = 1.15 M_s

Explanation:

Part a)

As we know that the period of revolution of the planet is given by

T = 2\pi\sqrt{\frac{r^3}{GM}}

now we know that

r = 10.5 \times 10^6 km = 1.05 \times 10^{10} m

T = 6.3 days

T = 5.44 \times 10^5 s

now we have

5.44 \times 10^5 = 2\pi\sqrt{\frac{(1.05\times 10^{10})^3}{(6.67 \times 10^{-11})M}}

M = 2.31 \times 10^{30} kg

Part b)

As we know that mass of sun is given as

M_s = 2.0 \times 10^{30} kg

now we have

\frac{M}{M_s} = \frac{2.31 \times 10^{30}}{2 \times 10^{30}}

M = 1.15 M_s

6 0
4 years ago
A 1.2-kg mass is projected from ground level with a velocity of 31.3 m/s at some unknown angle above the horizontal. A short tim
My name is Ann [436]

Answer:

The kinetic energy will be "399.65 J".

Explanation:

Given:

Mass,

m = 1.2 kg

Velocity,

v = 31.3 m/s

The total energy of mass will be:

⇒ E=K+U

or,

⇒ E=.5mv^2+mgh

By putting the values, we get

        =.5(1.2)(31.3)^2+0

        =0.6\times 979.69+0

        =587.81 \ J

Since,

The system's total energy is unchanged, then

⇒ E=K+U

or,

⇒ E=K+mgh

   587.81=K+1.2(9.8)(16)

   587.81=K+188.16

          K=587.81-188.16                

               =399.65 \ J

8 0
3 years ago
A wire carries a current of 6.52 A in a direction that makes an angle of 44.8 degrees with the direction of a magnetic field of
Komok [63]

Answer:

F=4.27N

Explanation:

From the question we are told that:

Current  I = 6.52 A

Angle \theta= 44.8 \textdegree

Magnetic field   B= 0.258 T.

Length l=3.61m

Generally the equation for  Magnetic force F is mathematically given by

 F=BIlsin\theta

Therefore

 F=0.258*6.52*3.61*sin 44.8

 F=4.27N

4 0
3 years ago
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