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3 years ago

To describe velocity you need to know _ and ___

Physics

2 answers:

Papessa [141]3 years ago

8 0

You need to know the distance and time

Crazy boy [7]3 years ago

5 0

To get the velocity you need to know the displacement and the time.

I hope that helps!

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Can someone please help me on number 4......

saw5 [17]

mass/volume = density.

if bigger than water, sinks

less than water floats.

Archimedes' principle, floatation, icebergs etc

7 0

4 years ago

Read 2 more answers

A 2.40 kg stone is sliding in the +x-direction on a horizontal, frictionless surface. It collides with a 4.00 kg stone at rest.

tester [92]

Answer:

4.32 kg.m/s

Explanation:

SInce the 2.4 kg stone is mobing at speed of 3.6m/s at an angle of 30 degree measured from the x+ direction toward y+ direction. Its y-component momentum is product of its velocity in the y-direction and its mass

$P_y = m*v_y = m*v*sin(\theta)$

$P_y = 2.4*3.6*sin(30)$

$P_y = 2.4*3.6*0.5 = 4.32 kg.m/s$

5 0

3 years ago

The system is released from rest with the cable taut, and the homogeneous cylinder does not slip on the rough incline. determine

dedylja [7]

Answer: hello your question is incomplete below is the complete question

answer : Angular acceleration = 7.88 rad/s^2 ( clockwise )

minimum coefficient of friction = -0.2225

Explanation:

First step : we calculate acceleration at point O

a = rα

acceleration at point A

aA = ( 2r ) α = 2α

∑Fy ( force in y axis ) = mass of block * aA

∴ T = mBlock ( g - 2α )

= 8.7 ( 9.81 - 2α )

attached below is the remaining part of the solution

6 0

4 years ago

In a Broadway performance, an 84.5-kg actor swings from a R = 4.30-m-long cable that is horizontal when he starts. At the bottom

Arada [10]

Answer:

1.57772 m

Explanation:

M = Mass of actor = 84.5 kg

m = Mass of costar = 55 kg

v = Velocity of costar

V = Velocity of actor

$h_i$ = Intial height of actor = 4.3 m

g = Acceleration due to gravity = 9.81 m/s²

As the energy of the system is conserved

$\frac{1}{2}MV^2=Mgh_i\\\Rightarrow V=\sqrt{2gh_i}\\\Rightarrow V=\sqrt{2\times 9.81\times 4.3}\\\Rightarrow V=9.18509\ m/s$

As the linear momentum is conserved

$MV=(m+M)v\\\Rightarrow v=\frac{MV}{m+M}\\\Rightarrow V=\frac{84.5\times 9.18509}{84.5+55}\\\Rightarrow v=5.56372\ m/s$

Applying conservation of energy again

$\frac{1}{2}(m+M)v^2=(m+M)gh_f\\\Rightarrow h_f=\frac{v^2}{2g}\\\Rightarrow h_f=\frac{5.56372^2}{2\times 9.81}\\\Rightarrow h_f=1.57772\ m$

The maximum height they reach is 1.57772 m

3 0

3 years ago

A substance maintaining a uniform appearance throughout

777dan777 [17]

Is there anything else you can add for context

5 0

3 years ago

To describe velocity you need to know _______ and _________

To describe velocity you need to know _ and ___