The solution would be like
this for this specific problem:
<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g =
v^2/r </span>
<span>v^2 = 4.5
g * r </span>
<span>v = sqrt
( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124
m/s</span>
So the pilot will black out for this dive at 124
m/s. I am hoping that these answers have satisfied your query and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.
The skier's speed at time <em>t</em> is
<em>v</em> = (23 m/s²) <em>t</em>
To reach a speed of 9.3 m/s, the skier would need
9.3 m/s = (23 m/s²) <em>t</em>
<em>t</em> = (9.3 m/s) / (23 m/s²)
<em>t</em> ≈ 0.404 s
Answer:
So the acceleration of the child will be 
Explanation:
We have given angular speed of the child 
Radius r = 4.65 m
Angular acceleration 
We know that linear velocity is given by 
We know that radial acceleration is given by 
Tangential acceleration is given by
So total acceleration will be 
Answer:
Energy is inversely proportional to wavelength.
Explanation:
The amount of energy, E, a wave carries is given as:
E = hf
where h = Planck's constant and f = frequency of the wave
Frequency and wavelength are related by the equation:
c = λf
=> f = c/λ
where λ = wavelength
Therefore, energy is:
E = hc/λ
This shows that energy is inversely proportional to wavelength. As wavelength increase, energy decreases and vice versa.
Answer:
Since the astronaut drops the rock, the initial velocity of the rock is 0 m/s
<u>We are given:</u>
initial velocity (u) = 0 m/s
final velocity (v) = v m/s
acceleration (a) = 1.62 m/s/s
height (h) = 1.25 m
<u>Solving for v:</u>
From the third equation of motion:
v²-u² = 2ah
replacing the variables
v² - (0)² =2 (1.62)(1.25)
v² = 1.62 * 2.5
v² = 4 (approx)
v = √4
v = 2 m/s
The speed of the rock just before it lands is 2 m/s
