Answer:
E. It may encourage a sense of entitlement among employees.
Explanation:
Above the market, compensation in the form of wage strategy in which the organizations initiates high salaries to the employees. High salaries are provided to the employees to attract them and to retain them in the team. This is done to maintain the caliber of the group and for the smooth flow among the team members.
Dividends= $ that people who bought stock in a company receive. Generally, these increase when the company is doing well.
Stock= becomes more expensive the better a company is doing and has been doing for a while because it is in higher demand.
I predict that the company's stock will rise because it is in higher demand based upon it's consistently doing well. Make sense?
<u>Solution and Explanation:</u>
As the utility function is concave in shape, so person is risk averse. Thus, he will not accept the gamvle.
The difference between utility at point A&C = 70 minus 65 = $5, is less than a the difference between A&B = 65 minus 55 = $10
<u>MCQ:
</u>
Answer is option a&d - risk averse people fear a lot for losing money, thus they overestimate the probability of loss
Since, shape of utility function is concave, hence the double derivative of utility with respect to wealth is negative, so utility falls at an decreasing rate , as wealth increases
Answer:
$30,900
Explanation:
The beginning finished goods is $15,400
Raw materials purchased is $18,800
The cost of goods manufactured is $34,100
Ending finished goods is $18,600
Therefore the cost of gods can be calculated as follows
= 15,400+34,100-18,600
= 49,500-18,600
= 30,900
Hence the cost of goods sold by the company is $30,900
Answer:
a) 0.0358
b) 0.0395
c) 0.1506
Explanation:
Number of clues "daily doubles" = 3
Determine the probabilities
<u>a) P(single contestant finds all three ) </u>
assuming event A= a returning champion gets the "daily double" in first trial
P(A) = 1/30 , P(~A) = 29/30
assuming event B = any player picks up "daily double" after the first move
P(B |~A ) = 1/3
hence : P ( B and ~A ) = 29/30 * 1/3 = 29/90
<em>considering second round </em>
P(player chooses both daily doubles ) = 1/3 * 1/3 = 1/9
∴ P(single contestant finds all three ) = 29/90 * 1/9 = 0.0358
<u>B) P ( returning champion gets all three ) </u>
= (1/30 + 29/90 )* 1/9
= 32 / 810 = 0.0395
<u>c) P ( each player selects only one )</u>
P = 32/405 + 29/405
= 61 / 405 = 0.1506
