Classify the following triangle. Check all that apply.

Mathematics

1 answer:

Vikentia [17]3 years ago

3 0

Answer:

it is an isosceles obtuse triangle.....

you can choose anyone

isosceles ( since two of its sides are equal but not the third)

or obtuse ( since one angle is more than 90)

You might be interested in

<img src="https://tex.z-dn.net/?f=5x%20-%2010%20%5Cleqslant%2020" id="TexFormula1" title="5x - 10 \leqslant 20" alt="5x - 10 \le

OlgaM077 [116]

The answer is x = 6
Explanation:
First, you must assume that 5x-10=20. Next, you add 10 to 20, which makes the equation 5x=30. Next, divide 30 by 5, which then makes the equation x=6. When you substitute 6 in the original equation, it works, because 5(6)-10 equals 20.

6 0

2 years ago

How to solve division with exponents

otez555 [7]

In division, exponents with the same base are subtracted.
example:
$\frac{x^4}{x^2} = x^2 \\ \\ \frac{ x^{3} y^{2} }{ x^{6} y} = \frac{y}{ x^{3} } \\ \\ Negative-exponents \\ \\ x^{-2} = \frac{1}{ x^{2} }$

5 0

2 years ago

In 2013, voyager 1 traveled 1,468,800 kilometers each day. Whats that in scientific notation

n200080 [17]

Answer: 1.4688 x 10^6

Step-by-step explanation: Number has to be in between 1 and 10. Moved the decimal 6 places so that is your exponent

8 0

2 years ago

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .