Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Answer:
b-14 = 9
b = 23
Step-by-step explanation:
Add 14 to 9 to get b alone.
Answer:
LM = 14
Step-by-step explanation:
LM = AC/2
LM = 28/2
<u>LM = 14</u>
Hope this helps!
Answer:
295
Step-by-step explanation:
.3 x 295 = 88.5
295 - 88.5 = 206.5
Answer:
up 2, right 3
Step-by-step explanation:
up 2, to the right 3.
