Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).
For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.
- The sample mean is of 15, thus
. - The sample standard deviation is of 9, thus
. - The sample size is of 10, thus
.
First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.
Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.
The margin of error is of:
Then:
The confidence interval is:
Then
The confidence interval is (9, 21).
A similar problem is given at brainly.com/question/25157574
Answer:
it is d i believe . hope this helps :)
Answer:
You can use a hint
Step-by-step explanation:
Press the Use a hint button, the first time it won't count, only then the second one won't count.
Answer:
36 students got an'A' grade in the quiz.
Step-by-step explanation:
Given:
Total number of students taking the quiz = 132
Fraction of students getting an 'A' grade = 
To find the number of students getting an 'A' grade.
Solution:
In order to find the number of students who got an 'A' grade in the quiz, we will find the fractional part who got an 'A' of the total students taking the quiz.
The fraction of students getting an 'A' is =
Thus, total number of student getting an 'A' is :
⇒ <em>of</em> 
⇒ 
⇒ 
⇒ 36 (Answer)
It is a straight horizontal line going through the Y axis at -2 :)
