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2 years ago

Which choice is a net of a triangular pyramid? A B C

Mathematics

1 answer:

gayaneshka [121]2 years ago

4 0

I think it A... But if it not sorry I didn’t help... hope this is the answer I am sure it is...

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Problem

Contact [7]

Answer:

<em>The width of the lid is 15 cm</em>

Step-by-step explanation:

<u>The Perimeter of a Rectangle</u>

Given a rectangle of width W and height H, the perimeter is calculated as:

P = 2(W + L)

Jon used 56 cm of ribbon to go around the edge of a rectangular lid. This means the perimeter is:

2(W + L) = 56

Dividing by 2:

W + L = 28

Since the lid was L=13 cm long, the width is:

W = 28 - 13 = 15

The width of the lid is 15 cm

8 0

3 years ago

Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)

timofeeve [1]

Answer: $x-2y-2=0$

Step-by-step explanation:

Given :

$f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8$

Point of intersection :

$f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}$

$x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75$

So, we have points $\left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )$

Equation of line passing through two points $\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )$

Let $\left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )$

So, equation is as follows :

$y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0$

4 0

3 years ago

Evaluate 6j+23+kl−3, when j=3, k=7, and l=33.

Dmitry [639]

Answer:

269

Step-by-step explanation:

6(3)+23+(7)(33)-3

\/ \/

18 + 23 + 231 - 3 = 269

3 0

2 years ago

A culture started with 4,000 bacteria. After 5 hours, it grew to 4,800 bacteria. Predict how many bacteria will be present after

eimsori [14]

First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646

Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours

Hope it helps!

4 0

3 years ago

Read 2 more answers

Suceción numerica 265 250 235 220 ____ ____ 175 ____ 145 130 ____ ____ ____ y aqui otra 4 12 36 ____ ____ ____ 2916 8748 ____ __

alina1380 [7]

Respuesta:

A la primera le vas a quitar 15 con cada número. A la segunda, todo lo multiplicas por 3 cada vez que vas avanzando.

265, 250 . . . 220, 205, 190, 175, 160, 145, 130, 115, 100, 185. ---------- 4, 12, 36, 108, 324, 972, 2,916, 8,748, 26,244, 78,732. ---------- 5, 20, 15, 40, 25, 60, 35, 80, 45, 90, 55, 100, 65, 110, 75. ---------- 30, 90, 270, 810, 2,430, 7,290, 21,870, 65,610, 196,830. ---------- 703125, 140625, 28125, 5625, 1125, 225, 45, 9. ---------- 36864, 9216, 2304, 576, 144, 36, 9, 2.25.

8 0

3 years ago