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satela [25.4K]
3 years ago
10

A quality-control plan calls for accepting a large lot of crankshaft bearings if a sample of seven is drawn and none are defecti

ve. What is the probability of accepting the lot if none in the lot are defective?
Mathematics
1 answer:
Viktor [21]3 years ago
4 0

Answer:

<u>The probability of accepting the lot if none in the lot are defective is </u><u>1</u>.

Step-by-step explanation:

A large lot of crankshaft bearings is accepted if 0 out of 7 are found defective. i.e. the probability of finding a defective crankshaft is 0.

Let X be the number of defective crankshafts. We need to find the probability that X=0. We will use the binomial distribution probability formula:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

           x = no. of successful trials

           p = probability of success

           q = probability of failure (1-p)

We have n=7, p=0, q=1.

P(X=0) = ⁷C₀ (0)⁰ (1)⁷⁻⁰

P(X=0) = 1

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1.23

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3 years ago
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Maurinko [17]

Answer:

Step-by-step explanation:

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charle [14.2K]

Value of x will be x=\frac{15}{a-b}.

Equation given in the question → ax=15+bx

To find the value of 'x' in terms of a and b, we will simplify the given equation,

ax=15+bx

ax-bx=(15+bx)-bx

x(a-b)=15

x=\frac{15}{a-b}

           Therefore, Values to filled → Blank 1 = 15

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Learn more,

brainly.com/question/14318220

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2 years ago
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3 years ago
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inna [77]

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Read 2 more answers
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