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Evgesh-ka [11]
3 years ago
5

A runner averages 8 minutes and 25 seconds per mile. What is her average velocity in miles per hour?

Chemistry
1 answer:
labwork [276]3 years ago
6 0

8 minutes and 25 seconds is the same as 8.25 in decimal form.

Divide by 60 minutes.

60 / 8.25 = 7.27 miles per hour

Best of Luck!

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Predict (to 3 sig figs) the isochoric specific heat of gaseous SF6 (molar mass 146.06 g/mol) at 1200 K, assuming that at this te
bazaltina [42]

Explanation:

As it is known that SF_{6} molecule is a non-linear molecule. Therefore, its isochoric heat capacity will be as follows.

              C_{v} = \frac{3}{2}R + \frac{3}{2}R + (3 \times 7 - 6)R

                         = \frac{3}{2}R + \frac{3}{2}R + 15R

                         = 18 R

Also,    C_{V} = M \times C_{v}

where,     C_{V} = molar heat capacity

                    M = molecular mass

               C_{v} = specific heat

Hence, calculate the value of C_{v} as follows.

                 C_{V} = M \times C_{v}

               8 \times 8.314 \times 10^{7} = 146.06 \times C_{v}

               C_{v} = 10.2 \times 10^{6} erg. K^{-1}. gm^{-1}

This means that value of isochoric specific heat is 10.2 \times 10^{6} erg. K^{-1}. gm^{-1}.

Yes, we have to assume ideal gas behavior because for ideal gas:

                         dU = nC_{v}dT

Whereas for real gases "\frac{an^{2}}{V^{2}}" has to be added here.

5 0
3 years ago
Which structures help plants control the rate of transpiration to prevent withering and eventual death?
Luba_88 [7]

Answer:

C - guard cells and stomata

Explanation:

8 0
3 years ago
Read 2 more answers
15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl
Shkiper50 [21]

Answer:

41.56 g

Explanation:

Given data:

Mass of NH₄Cl = 15.50 g

Actual yield of AgCl = 35.50 g

Theoretical yield of AgCl = ?

Solution:

Chemical equation:

NH₄Cl  + AgNO₃      →     AgCl   + NH₄NO₃

Number of moles of NH₄Cl:

Number of moles = mass/ molar mass

Number of moles = 15.50 g/ 53.491 g/mol

Number of moles = 0.29 mol

Now we will compare the moles of NH₄Cl with   AgCl .

                     NH₄Cl            :               AgCl

                        1                  :                 1

                     0.29              :                0.29

Theoretical yield of AgCl:

Mass = number of moles × molar mass

Mass = 0.29 mol ×143.32 g/mol

Mass = 41.56 g

4 0
3 years ago
How many grams of cuno3 will be required to make 1.00 l of 0.420 m solution?
7nadin3 [17]

Answer:

The answer to your question is:  52.92 g of CuNO₃

Explanation:

Data

grams of CuNO₃ = ?

volume = 1 l

concentration = 0.420 M

MW of  CuNO₃ = 64 + 14 + 3(16) = 126 g

Formula

Molarity = moles / volume

moles = Molarity x volume

moles = 0.420 x 1

moles = 0.420 moles

                                    1 mol of CuNO₃  -------------------  126 g of CuNO₃

                                  0.420 moles CuNO₃ -------------    x

                                    x = (0.420 x 126) / 1

                                    x = 52.92 g of CuNO₃

3 0
3 years ago
1 cg is equal to (2 points) Select one: a. 103 hg. b. 103 g. c. 10-2 mg. d. 10-2 g.
Semmy [17]
The answer should be D) 10-2 g.
3 0
3 years ago
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