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Contact [7]
3 years ago
12

How many grams of cuno3 will be required to make 1.00 l of 0.420 m solution?

Chemistry
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

The answer to your question is:  52.92 g of CuNO₃

Explanation:

Data

grams of CuNO₃ = ?

volume = 1 l

concentration = 0.420 M

MW of  CuNO₃ = 64 + 14 + 3(16) = 126 g

Formula

Molarity = moles / volume

moles = Molarity x volume

moles = 0.420 x 1

moles = 0.420 moles

                                    1 mol of CuNO₃  -------------------  126 g of CuNO₃

                                  0.420 moles CuNO₃ -------------    x

                                    x = (0.420 x 126) / 1

                                    x = 52.92 g of CuNO₃

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