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3 years ago

How many grams of cuno3 will be required to make 1.00 l of 0.420 m solution?

Chemistry

1 answer:

7nadin3 [17]3 years ago

3 0

Answer:

The answer to your question is: 52.92 g of CuNO₃

Explanation:

Data

grams of CuNO₃ = ?

volume = 1 l

concentration = 0.420 M

MW of CuNO₃ = 64 + 14 + 3(16) = 126 g

Formula

Molarity = moles / volume

moles = Molarity x volume

moles = 0.420 x 1

moles = 0.420 moles

1 mol of CuNO₃ ------------------- 126 g of CuNO₃

0.420 moles CuNO₃ ------------- x

x = (0.420 x 126) / 1

x = 52.92 g of CuNO₃

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