Answer:
The answer to your question is C₃H₂O₁ or C₃H₂O
Step-by-step explanation:
Data
mass of protein = 0.105 g
elements = C, H, O
mass of CO₂ = 0.257 g
molar mass of CO₂ = 44.01 g/mol
mass of water = 0.035 g
molar mass of water = 18.02 g/mol
empirical formula = ?
Process
1.- Calculate the mass and moles of carbon
44 g of CO₂ ------------ 12 g of C
0.257 g of CO₂------------- x
x = (0.257 x 12)/44
x = 3.084/44
x = 0.07 g of Carbon
12 g of C ----------------- 1 mol
0.07 g of C ------------- x
x = (0.07 x 1) / 12
x = 0.0058 moles of C
2.- Calculate the mass and moles of H
18 g of H₂O --------------- 2 g of H
0.035 g of H₂O ---------- x
x = (0.035 x 2) / 18
x = 0.0039 g of H₂
1 g of H ------------------- 1 mol of H
0.0039 g of H --------- x
x = 0.0039 moles of H
3.- Calculate the mass and moles of O₂
mass of O₂ = 0.105g - 0.07 - 0.0039g
= 0.0311 g of O₂
16 g of O₂ -------------- 1 mol
0.0311 f of O₂ --------- x
x = (0.0311 x 1)/16
x = 0.0019 moles of O₂
4.- Divide by the lowest number of moles
Carbon = 0.0058 / 0.0019 = 3.0
Hydrogen = 0.0039 / 0.0019 = 2.0
Oxigen = 0.0019 / 0.0019 = 1
5.- Write the empirical formula
C₃H₂O₁ or C₃H₂O
