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Drupady [299]
3 years ago
10

I need it quickly…….

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
6 0

Answer:

I think it's A.

kirill [66]3 years ago
4 0
Yep he or she is right have a nice day
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Help 25 points<br> Quick sue tommorow
algol [13]

Answer:

Try distributing numbers by multiplying

6 0
3 years ago
All fractions equivalent to 27/81
Strike441 [17]
There is more than a trillion of equivalent fractions to 27/81, you just need to divide of multiply that number to any other numbers, but not 1 and 0, it can be negative number also
Ex: 1/3, 3/9, 54/12, 81/243, etc...
3 0
4 years ago
100 Points and Brainliest.
hichkok12 [17]

Answer:

See below ↓

Step-by-step explanation:

We have a graph given to us.

⇒ Take the points to form an equation!

<u>The points</u>

  • (4, 6)
  • (-2, 1)

<u>Making an equation</u>

  • Find the slope
  • m = 1 - 6 / -2 - 4
  • m = -5 / -6
  • m = 5/6

  • Take one of the two points and substitute in the equation :
  • ⇒ y - y₁ = m (x - x₁)
  • ⇒ y - 6 = 5/6 (x - 4)
  • ⇒ y - 6 = 5x/6 - 10/3
  • ⇒ <u>y = 5x/6 + 8/3</u>
  • ⇒ or <u>6y = 5x + 16</u>
3 0
2 years ago
Read 2 more answers
Can someone help me please
Ede4ka [16]
What do you need help with I can’t read the thing
3 0
3 years ago
(a) Write down the gradient of the line with equation y = 7 - 4x The line L passes through the points with coordinates (- 3, 1)
lesya [120]

Note: Let us consider, we need to find the gradient of line L.

Given:

The given equation of a line is:

y=7-4x

The line L passes through the points with coordinates (- 3, 1) and (2, - 2).

To find:

The gradient of the given line and the gradient of line L.

Solution:

Slope intercept form of a line is:

y=mx+b                ...(i)

We have,

y=7-4x                   ...(ii)

On comparing (i) and (ii), we get

m=-4

Therefore, the gradient of the given line is -4.

The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-2-1}{2-(-3)}

m=\dfrac{-3}{2+3}

m=\dfrac{-3}{5}

Therefore, the gradient of the line L is \dfrac{-3}{5}.

6 0
3 years ago
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