Answer:
What is the question??
Step-by-step explanation:
If it is who ran more than it would be Hector
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
What you have to do to find the median of the data is first put that data into order numerically. You can go largest to smallest or smallest to largest, it doesn't matter. <span>
22, 24, 28, 28, 30, 31, 31, 32, 32, 35, 36, 37, 38, 41, 42, 42, 44, 44, 45, 46, 46, 47, 47, 49, 50
Once you put them into order, you count towards the middle. You have 25 data points, so the middle, which will be your median number, will be 13 points in.
The median is 38</span>
T = # of text messages
$91.50 = 0.45t + $50
Subtract 50 from both sides
$41.50 = 0.45t
divide by 0.45
92.2 = # of text messages David had