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liubo4ka [24]
3 years ago
9

What’s the result ????????????????

Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

Option 1

Step-by-step explanation:

You must multiply (2x + 3) by (x + 4). I use the FOIL method.

(2x + 3)(x + 4)

Multiply

2x² + 8x +3x + 12

Simplify

2x² + 11x + 12

To check the answer, you could factor this trinomial back into a pair of binomials.

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Janet reads 1/8 of her book on Monday.She reads another 2/8 of the book on Tuesday. How much of the book remain unread?
xxTIMURxx [149]
So just add 1/8 and 2/8. add 1 plus 2 and the denominator (bottom number) stays the same so you get 3/8 then subtract 8/8 minus 3/8 so just 8 minus 3 is 5 and the denominator stays the same so you end up with 5/8 so 5/8 of the book remains unread
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2 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

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The difference of the measures of two supplementary angles is 80°. find the measure of each angle.
telo118 [61]
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4 0
3 years ago
Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away
Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

\triangle ABD\sim \triangle ECD

\frac{AB}{EC}=\frac{BD}{CD}

Substitute the values

\frac{AB}{1.45}=\frac{31.65}{5.45}

AB=\frac{31.65\times 1.45}{5.45}

AB=8.42m

Hence, the height of the tree=8.42 m

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