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2 years ago

Janet reads 1/8 of her book on Monday.She reads another 2/8 of the book on Tuesday. How much of the book remain unread?

1 answer:

7 0

So just add 1/8 and 2/8. add 1 plus 2 and the denominator (bottom number) stays the same so you get 3/8 then subtract 8/8 minus 3/8 so just 8 minus 3 is 5 and the denominator stays the same so you end up with 5/8 so 5/8 of the book remains unread

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What is the slope of the line 3y=6x-1

Allisa [31]

Answer:

Step-by-step explanation:

Simplify 3y=6x+1;

y=2x-1/3

y=mx+b , where m represents the slope.

Slope; 2

6 0

2 years ago

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Sami has 89 video games. He keeps 14 for himself and distributes the remaining video games to each

Natasha2012 [34]

Answer:

89=14-5x

Step by step

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3 years ago

HELP ASAPJennifer and Chris completed some chores and split the earnings in the ratio 3:2. Jennifer earned $48.

elixir [45]

Let the total earnings be = x

Jennifer and Chris split the earnings in the ratio 3:2

Jennifer earned = $48

$\frac{3x}{5}=48$

$3x=240$

x=80

Hence total earnings are $80

(a) Chris earning is = $\frac{2x}{5}=\frac{2*80}{5}=32$

Hence, Chris earns $32

(b) Jennifer spends 30% of her earnings on a book.

So, price of the book = $\frac{30}{100}\times48$

Price of book = $14.40

(c) Jennifer also buys a magazine for = $5.40

So, total money Jennifer spent on book and magazine = 14.40+5.40=19.80

Money left with Jennifer = 48-19.80= $28.20

In fractions = $\frac{28.20}{48}$

or multiplying the numerator and denominator by 10, we get

$\frac{282}{480}$ = $\frac{47}{80}$

(d) Let the original price of the shirt = x

reduction percentage on x= 40%

Price paid after reduction = 16.80

$\frac{40x}{100}=16.80$

$40x=1680$

$x=42$

Hence, the original price of the shirt was $42.

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3 years ago

A mother is 13/4 times as tall as her son. Her son is 3 feet tall how tall is the mother.

Kazeer [188]

They’re both really y’all

7 0

3 years ago

Read 2 more answers

Limit

STatiana [176]

Rationalize the numerator:

$\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}$

This is continuous at $x=0$ , so we can evaluate the limit directly by substitution:

$\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14$

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3 years ago