Answer:
DNE
Step-by-step explanation:
The left limit is +1; the right limit is -1. These are different, so the limit does not exist.
The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.
Suppose you roll a red number cube and a blue number cube. What is the probability that you will roll a 5 on the red cube and a 1 or 2 on the blue cube?
The answer to the first question of the attached document is option 1. We obtain the answer subtracting the term n from the series with the term n-1.For example:
-3 - (- 5) = 2
-1 - (- 3) = 2
1 - (- 1) = 2
So you can see that the common difference is the 2.
The answer to the second question is option 3:
y = | x + 7 |
We can confirm it by substituting values in the equation.
For example:
if we do y = 0 then x = -7
if we do x = 0 then y = 7.
As corresponds in the graph shown.
Remember also that as a general rule yes to the equationy = | x | whose vertex is in the point (0,0) we add a positive real number "a" of form y = | x + a | then the graph of y = | x | will move "to" units in the negative direction of x.
The answer to the third question is option 4.
The quotient of x and "and" is constant.
k = y / x
Rewriting:
y = kx
You can see that it corresponds to the equation of a line that passes through the origin, this means that and is proportional to x and both vary directly
So with this, you can rewrite the equation as: 
Firstly, solve the multiplication: 
Next, combine like terms, and <u>your answer will be: 
</u>
