X^2 - 10x + 8 =0
x^2 - 10 + (-10/2)^2 - (-10/2)^2 + 8 = 0
(x - 5)^2 - 25 + 8 = 0
(x - 5)^2 - 17 = 0
To be honest , this is the final step for this equation. It seems like there is no any suitable answer for this question..
To me , I think the best answer will be the third option.
x - 5 =0
x = 5
2x-10 = 0
2x = 10
x = 5
I guess this answer seems like legit.. So I will choose the third option.
Answer:
Step-by-step explanation:
Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.
We know that 
so there exists integers k,m such that a = kd and b = md. Then,
. Recall that since k, x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.
Answer:
answer is 0
Step-by-step explanation:
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
Answer:
Step-by-step explanation:
