PLease help me on this I have ten minutes left

M times the quotient of 10 and 7

Ad libitum [116K]

10 / 7 *m or m(10/7)

4 0

3 years ago

An NBA fan named Mark claims that there are more fouls called on his team 1 point

inn [45]

Answer:

$t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551$

$df = n-1=34-1=33$

$p_v =P(t_{(33)}>2.551)=0.008$

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

Step-by-step explanation:

Information provided

$\bar X=12.2$ represent the sample mean fould against

$s=1.6$ represent the sample standard deviation

$n=34$ sample size

represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is higher than 11.5 fouls per game:

Null hypothesis: $\mu \leq 11.5$

Alternative hypothesis: $\mu > 11.5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551$

P value

The degreed of freedom are given by:

$df = n-1=34-1=33$

Since is a one side test the p value would be:

$p_v =P(t_{(33)}>2.551)=0.008$

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

7 0

2 years ago

What is D and R? Please answer I need help.

Setler79 [48]

Answer:

31. D: {8, 4, 0, -4}; R: {2, -1}; yes

32. D: {-1, 2, 7}; R: {-4, -3, -2, 0}; no

33. D: {-4, -3, -1, 2, 3, 5}; R: {-3, -2, 0, 3, 5}; yes

34. D: (-∞, ∞); R: (-∞, 4]; yes

35. D: [0, 5]; R: [-2, 3]; no

Step-by-step explanation:

In this context, D means "domain" and R means "range." The domain of a function is the list of input values for which the function is defined. For ordered pairs, it is the first number of the pair. For an x-y table, it is the list of x-values. For a graph, it is the possible values of x.

A relation is a <em>function</em> only if there are no repeated values in the domain (2 or more outputs for the same input.)

The range of a function is the list of output values produced by the function. For ordered pairs, it is the second number of the pair. For an x-y table, it is the list of y-values. For a graph, it is the possible values of y.

__

31. D: {8, 4, 0, -4}

R: {2, -1}

Function: yes

Domain and range values don't need to be repeated. Often, they're listed in order from lowest to highest. Here, we have listed them in order of occurrence in the function definition.

__

32. D: {-1, 2, 7}

R: {-4, -3, -2, 0}

Function: no

__

33. D: {-4, -3, -1, 2, 3, 5}

R: {-3, -2, 0, 3, 5}

Function: yes

__

34. D: (-∞, ∞)

R: (-∞, 4]

Function: yes

__

35. D: [0, 5]

R: [-2, 3]

Function: no . . . . . . there are 2 y-values for most x-values

4 0

3 years ago

What’s the students GPA?

andreyandreev [35.5K]

Answer:

The student's GPA is 2.8666.

Step-by-step explanation:

A grade is 4.0, B grade is 3.0, C grade is 2.0. For each credit, add the value of the letter grade. So:

Math, 2 credits, grade A: (4x2=8)

English, 5 credits, grade B: (5x3=15)

Physics, 4 credits, grade B: (4x3=12)

German, 4 credits, grade C: (4x2=8)

The numbers add up to 43, then divide by the number of credits (15) to get:

43/15=GPA of 2.8666.

6 0

3 years ago

A large university accepts 50% of the students who apply. Of the students the university accepts, 35% actually enroll. If 10,

lara31 [8.8K]

Answer:

3,500 students

Equation:

0.35 x 10,000 = 3,500

8 0

2 years ago