Answer:
2.
Step-by-step explanation:
Since 3 hours and $15 an hour
Hello from MrBillDoesMath!
Answer:
(3/4) a^(-5)b^(-3)c^2
Discussion:
(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =
(18/24) a^ (-3-2) b^(2-5) c^(6-4) =
as a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples
(3/4) a^(-5)b^(-3)c^2
Thank you,
MrB
Answer:
$665.36
Step-by-step explanation:
2^16 or...
2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2 = 66536 pennies
Answer:

Step-by-step explanation:
Tan can be defined as:
as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.
Using this we can define tan
