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Softa [21]
3 years ago
6

PLease help me on this I have ten minutes left

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0

Answer:

4

Step-by-step explanation:

You might be interested in
According to this diagram, what is tan 67° ?
Zanzabum

Answer:

B. 12/5

Step-by-step explanation:

tan=opp. leg/adj. leg

tan 67= 12/5

6 0
3 years ago
Read 2 more answers
The lines on a 2-cup liquid measuring cup divide each cup into eighths. If you measure 1 3/4 cups of water, between which two qu
masya89 [10]

Answer:

1 3/4 cups is between the 13th and 15th lines from the bottom.

Step-by-step explanation:

The bottom of the cup has no line and corresponds to 0 eights.

1st line up: 1/8 cup  

2nd line up: 2/8 cup    this is also called 1/4 cup

3rd line up: 3/8 cup

4th line up: 4/8 cup     this is also called 1/2 cup

5th line up: 5/8 cup

6th line up: 6/8 cup     this is also called 3/4 cup

7th line up: 7/8 cup

8th line up: 8/8 cup     this is also called 1 cup

9th line up: 9/8 cup

10th line up: 10/8 cup    this is also called 1 1/4 cup

11th line up: 1 3/8 cup

12th line up: 1 4/8 cup     this is also called 1 1/2 cup

13th line up: 1 5/8 cup

14th line up: 1 6/8 cup    this is also called 1 3/4 cup

15th line up: 1 7/8 cup

16th line up: 1 8/8 cup    this is also called 2 cups

1 3/4 cups is between the 13th and 15th lines from the bottom.

7 0
3 years ago
Please help me I’m terrible at math
irga5000 [103]

Answer:

...

Step-by-step explanation:

can you show us the options of the drop-down menus?

8 0
3 years ago
Meh needs some help once again
Ymorist [56]
1:1 because you simplify
7 0
3 years ago
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
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