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Ilia_Sergeevich [38]
3 years ago
15

Evaluate b-(-1/8)+c where b=2 and c=-7/4​

Mathematics
1 answer:
tatiyna3 years ago
8 0

Answer:

3/8

Step-by-step explanation:

Evaluate b - -1/8 + c where b = 2 and c = -7/4:

b - (-1)/8 + c = 2 - (-1)/8 - 7/4

Put 2 + 1/8 - 7/4 over the common denominator 8. 2 + 1/8 - 7/4 = (8×2)/8 + 1/8 + (2 (-7))/8:

(8×2)/8 + 1/8 - (7×2)/8

8×2 = 16:

16/8 + 1/8 - (7×2)/8

2 (-7) = -14:

16/8 + 1/8 + (-14)/8

16/8 + 1/8 - 14/8 = (16 + 1 - 14)/8:

(16 + 1 - 14)/8

16 + 1 = 17:

(17 - 14)/8

| 1 | 7

- | 1 | 4

| 0 | 3:

Answer:  3/8

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List all elements of each set. (Note that sometimes you will have to put three dots at the end, because a set is infinite.)
ryzh [129]

Answer:

0, 1, 2, 3, 4, 5

Step-by-step explanation:

When you divide a natural number by 6, the remainders you can get are 0, 1, 2, 3, 4, and 5. Hope this helps!

6 0
3 years ago
How do i answer this question?
blondinia [14]

Answer:

f^{-1} (59) = 20

Step-by-step explanation:

f^{-1} (x) is the inverse of f(x)

to find the inverse function, let f(x) = y and rearrange to make x the subject.

y = 3x - 1 ( add 1 to both sides )

y + 1 = 3x ( divide both sides by 3 )

\frac{y+1}{3} = x

change y back into terms of x with x = f^{-1} (x) , then

f^{-1} (x) = \frac{x+1}{3} , then

f^{-1} (59) = \frac{59+1}{3} = \frac{60}{3} = 20

7 0
3 years ago
Read 2 more answers
ANSWER FOR BRAINLIEST<br> Identify the graph for the point C(−2, −1, 2) in three-dimensional space.
ioda

Answer:

the topmost one maybe?

Step-by-step explanation:

I'm guessing since X & Y are negative, (it's written X,Y,Z, right?)

The point would be reducing on the X&Y axes, an since Z is positive, it would increase on the Z axis

4 0
3 years ago
What are 3 consecutive integers whose product is -120
iren2701 [21]
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero

x+6=0
x=-6

x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6



use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1

the numbers are -4,-5,-6
5 0
3 years ago
Simplify the algebraic expression (4b5 - 7) + (12b5 - 1)
ioda

Answer:16b square root of 5 -8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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