All categories

3 years ago

Evaluate b-(-1/8)+c where b=2 and c=-7/4

Mathematics

1 answer:

tatiyna3 years ago

8 0

Answer:

3/8

Step-by-step explanation:

Evaluate b - -1/8 + c where b = 2 and c = -7/4:

b - (-1)/8 + c = 2 - (-1)/8 - 7/4

Put 2 + 1/8 - 7/4 over the common denominator 8. 2 + 1/8 - 7/4 = (8×2)/8 + 1/8 + (2 (-7))/8:

(8×2)/8 + 1/8 - (7×2)/8

8×2 = 16:

16/8 + 1/8 - (7×2)/8

2 (-7) = -14:

16/8 + 1/8 + (-14)/8

16/8 + 1/8 - 14/8 = (16 + 1 - 14)/8:

(16 + 1 - 14)/8

16 + 1 = 17:

(17 - 14)/8

| 1 | 7

- | 1 | 4

| 0 | 3:

Answer: 3/8

You might be interested in

17. Joan's Candy Emporium is having a sale. Three pounds of gummy bunnies are

Kazeer [188]

Answer:

$1.99 per pound

Step-by-step explanation:

5.97 / 3 = 1.99

5 0

3 years ago

Solve 7x-2x(x+1)=6x+14 A) x=-12 B) x=12 C) x=-16 D) x=16

prisoha [69]

Answer:

x=-16 (answer : C

Step-by-step explanation:

hello:

put x=-16 in this equation : 7x-2(x+1)=6x+14

7(-16)-2(-16+1)=6(-16)+14

-112-2(-15) = -96+14

-112+30= -96+14

-82 = -82 .....true

3 0

3 years ago

2/7x14 multiply answer

Ratling [72]

Answer:

$4$

Step-by-step explanation:

$\frac{2}{7} \times 14 \\ \\ 2 \times 2 = 4$

4 0

4 years ago

Q20-23 with steps pls

just olya [345]

20: Let $x$ be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

$\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30$

Rearrange the left hand side as

$\dfrac{4x-3x}{24}=30$

And multiply both sides by 24 to get

$x=720$

21: Let $M$ and $J$ be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

$M=3J+11$

If they both get 9 more marbles, Mike will have $M+9$ marbles, and Judy will have $J+9$ marbles. So, we have

$M+J+18=93 \iff M+J=75 \iff M=75-J$

Plug this value in the first equation and we have

$75-J=3J+11 \iff 4J=64 \iff J=16$

And we deduce

$M=16\cdot 3 + 11=59$

So, the difference is

$M-J=59-16=43$

22: Let $x,y,z$ be the number of $10, $20 and $50 coupon, respectively. We're given:

$\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}
We can write the third equation by substituting the expressions for x and z:
[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38$