Ask question

Ask question

All categories

3 years ago

9

50% of babies are born female. Olive wants to find the probability that 20 or more of the 50 babies born today were female. Use

the simulation data to find the probability. Round to the nearest percent.

2 answers:

laila [671]3 years ago

7 0

It is 94%. Add everything from 20-21 all the way onwards and divide by 200. Then multiply by 100.

Len [333]3 years ago

6 0

Answer:

94% is right

Step-by-step explanation:

‍

You might be interested in

Tom has 12.42 centimeters of yarn. If he wants to make the yarn into pieces that are 0.54 centimeters long, how many pieces can

natta225 [31]

Answer:

23 pieces of yarn

Step-by-step explanation:

12.42cm divided by 0.54cm = 23

pls mark brainliest....:)

5 0

3 years ago

Please help me with this

Arturiano [62]

Answer:

C

Step-by-step explanation:

4 0

4 years ago

What is -2 sqrt 50 - sqrt 125 in simplest radical form

Gnoma [55]

Answer:

- 10√2 - 5√5

Step-by-step explanation:

- 2√50

√50 = √( 2 x 5 x 5 ) = 5√2

- 2√50

= - 2 x 5√2

= - 10√2

- √125

= - √( 5 x 5 x 5 )

= - 5√5

- 2√50 - √125

= - 10√2 - 5√5

6 0

2 years ago

Read 2 more answers

Which situation can be represented by 16 x 4?

Alex787 [66]

Answer:

the answer should be c.

Step-by-step explanation:

here's why....A uses 4 more which is adding. B uses 4 fewer which is subtracting and D does not complete so it should be C.

6 0

3 years ago

Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0

erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

$15x^2-kx+1=0$ (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

$2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8$

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

$15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}$

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0

4 years ago