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4 years ago

7

What is the value of x in the equation Negative two-thirds x + 9 = four-thirds x minus 3?

2 answers:

pychu [463]4 years ago

5 0

Answer:

<u>x=6</u>

What is the value of x in the equation Negative two-thirds x + 9 = four-thirds x minus 3?

KIM [24]4 years ago

4 0

Answer:

x=6

Step-by-step explanation:

Can you please give me the braily

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What is the simplest form of the quotient 4 square root 810 over 4 square root 2

Len [333]

Answer:

$3\sqrt[4]{5}$

Step-by-step explanation:

Given: $\frac{\sqrt[4]{810} }{\sqrt[4]{2} }$

Top and bottom has fourth root. so we take fourth root in common

$\sqrt[4]{\frac{810}{2} }$

When we divide 810 by 2. we will get 405

$\sqrt[4]{405}$

Now we simplify the fourth root

405 can be written as 3*3*3*3*5

$\sqrt[4]{3*3*3*3*5}$

$3\sqrt[4]{5}$

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3 years ago

Let D be a region bounded by a simple closed path C in the xy-plane. The coordinates of the centroid ( , ) of D are given below,

san4es73 [151]

Answer:

the answer is- 0.09

Step-by-step explanation:

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3 0

3 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set. (

algol13

Answer:

its correct answer is

{y}

7 0

3 years ago

Examine the following graph, where P(x) is the preimage and I(x) is the image after a transformation.

Arisa [49]

Answer:

the 4th answer I(x) = P(x-4)

Step-by-step explanation:

the first 2 options are out, because just adding values to the functional result values changes the y value, and the curve is pushed up or down. but not to the side.

just imagine

I(x) = P(x-4) means that the function value of previously at x-4 happens now at x. 4 units "later" (or more to the right).

"x+4" would make the functional value at previously x+4 happen now at x. so, everything would shift to the left (happen "earlier").

therefore, the 4th answer option is correct.

3 0

2 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0

2 years ago