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Alja [10]
3 years ago
15

What is the product of two and +5 squared

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

50 ...................

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Please find the m∠DEY
GrogVix [38]

Answer:

41, x=-5

Step-by-step explanation:

m<DEY = m<FEY, by angle bisector theorem

(9x-4) = 41

9x = 45

x = 5

m<DEY = 41

6 0
3 years ago
4 to 7 equals 21 to what ​
Margaret [11]
Can you show the whole question
8 0
3 years ago
Read 2 more answers
X4⋅x5=x20 <br><br> Group of answer choices<br><br> True<br><br> False
Gnoma [55]

Answer:

True.

Step-by-step explanation:

It explains itself right

3 0
3 years ago
A river discharges 4 × 106 cubic feet of water into the Pacific Ocean each second. There are 86,400 seconds in one day. To find
erik [133]

Answer:

3.456E + 14= 3.456X10^{14

Step-by-step explanation:

The river discharges 4X10^6 cubic feet of water into the Pacific Ocean each second.

There are 86,400 seconds in one day.

Amount of water discharges each day

=4X10^6X86400\\=345600000000\\=3.456X10^{11

Since this differs from what you have, I will explain the scientific notation.

3.456E + 14 simply means 3.456X10^{14

The options are not well laid out but you can pick the appropriate option.

8 0
4 years ago
Please help!!!
Leto [7]

Answer:

 - The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

- The scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse} and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).

Step-by-step explanation:

 You can observe in the figure attached that  "AC" is the distance between the Sun and the shooting star.

Knowing the distance between the Earth and the Sun "y" and the angle x°,  the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

 This is:

cos\alpha=\frac{adjacent}{hypotenuse}

In this case:

\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC

Therefore, the scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse} , and solve for the distance between the Sun and the shooting star "AC":

cos(x\°)=\frac{y}{AC}

AC=\frac{y}{cos(x\°)}

3 0
4 years ago
Read 2 more answers
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