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guapka [62]
2 years ago
5

Please help me!!!!!!

Mathematics
2 answers:
Ivan2 years ago
7 0

Answer:

please the answer is the third option

Vitek1552 [10]2 years ago
4 0

Answer:

B. - x+17/12

Step-by-step explanation:

2x-1/3 - 3x+7/4 cress cross

4(2x-1) + 3(-3x +7)/12

8x-4 - 9x+12/12

-1x + 21-4/12

-x+17/12

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a 20 ft piece of string is cut into two pieces so that the longer piece is 5 feet longer than twice the shorter piece. If the sh
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Longer piece is 15 and shorter piece is 5
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Need help with these two percentages...<br>1) Increase 480 by 1 % <br>2) Decrease 180 by 13 %
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2.156.6

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6 0
3 years ago
Every time Luisa bakes a batch of brownies she uses 1/2 cup of chocolate if she has 3/2 cups of chocolate remaining how many bat
kakasveta [241]

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she can make 4 batches of brownies

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3 0
3 years ago
12 is what percentage of 80
PIT_PIT [208]

Answer:  " 15 % " .

_______________________________

     →   " 12 is <u>  15% </u> of 80 " .

_______________________________

Step-by-step explanation:

_______________________________

12 = (n/100) * 80 ;

12 = (80n) /100 ;  Solve for "n:

Note:  80/100 = (80/10) / (100/10) = (8/10) = 0.8  ;

12 = (0.8)n  ;

↔ (0.8n) = 12

Multiply each side of the equation by "10" ; to get rid of the "decimal" ;

 10 * (0.8n) = 10 * 12 ;

to get:

_______________________________

8n = 120 ;

Divide each side of the equation by "8" ;

to isolate "n" on ONE SIDE of the equation; & to solve for "n" ;

8n/8 = 120/ 8 ;

_______________________________

to get:

_______________________________

n = 15 .

_______________________________

Answer:  " 15 % " .

_______________________________

     →   " 12 is <u>  15% </u> of 80 " .

_______________________________

Hope this helps!

Best wishes!

_______________________________

4 0
3 years ago
A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.
steposvetlana [31]
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term. 
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression

7 0
3 years ago
Read 2 more answers
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