1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babymother [125]
3 years ago
5

Graph the ordered pairs for y = 2x + 4 using x={−2,  1, 2} ? plz help!!

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0
(-2,0), (1,6), and (2,8)
Rina8888 [55]3 years ago
6 0
(-2, 0), (1, 6), and (2, 8)
You might be interested in
Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70
kumpel [21]

Answer:

His acceleration is \frac{1}{15} meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is a=\frac{v_{f}-v_{i}}{t} , where

  • v_{f} is the final speed
  • v_{i} is the initial speed
  • The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

   106 meters/minute (final speed) in 9 seconds

∴ His initial speed v_{i} = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ \frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}  meters/second

∴ v_{i} = \frac{7}{6}  meters/second

∵ His final speed v_{f} = 106 meters/minute

- Change it the meter per second

∴ \frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}  meters/second

∴ v_{f} = \frac{53}{30}  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is a=\frac{v_{f}-v_{i}}{t}

- Substitute the values of t, v_{i}  and v_{f} in the formula above

∴  a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}

∴ His acceleration is \frac{1}{15} meters per seconds²

3 0
3 years ago
Look at image............
zheka24 [161]

Answer:

f(x)=2x-3

Step-by-step explanation:

cause fir example if you put x=2 the y became 1.

4 0
2 years ago
Write an equation for the line graphed.
Kay [80]

Answer:

the answer is "d" because the x region is negative 2 and the y region is a positive1

6 0
3 years ago
Solve the inequality
Marianna [84]

Answer:

The answer to your question is the letter A) x ≥ 0.5

Step-by-step explanation:

Inequality

                           2(4x - 3) ≥ -3(3x) + 5x

Process

1.- Expand

                            8x - 6 ≥  - 9x + 5x

2.- Simplify

                            8x - 6 ≥ - 4x

3.- Add 6 units in both sides

                           8x - 6 + 6 ≥ -4x + 6

4.- Simplify

                                8x ≥ -4x + 6

5.- Add 4x in both sides

                                8x + 4x ≥ -4x + 6 + 4x

6.- Simplify

                                12x ≥ 6

7.- Divide by 12 both sides

                                12x/12 ≥ 6/12

8.- Simplify

                                    x ≥ 1/2  or 0.5

8 0
4 years ago
Read 2 more answers
Write an equation that models each of the following translation
Viefleur [7K]

Answer:

y = 2sinx + 2

Step-by-step explanation:

∵ y = Asin(Bx - C) + D

∵ D is the vertically shift

∵ It moves 2 units up

∴ D = 2

∴ y = 2sinx + 2

5 0
3 years ago
Other questions:
  • Which statement about g in quadrilateral WXYZ is correct?
    14·1 answer
  • PLEASE HELP To find the quotient 2 over 5 divided by 1 over 4
    11·2 answers
  • Jet A can fly 510 miles in 5 hours while Jet B can fly 460 miles in 4 hours. Which jet has a better rate?
    11·1 answer
  • What's the answer will award brainiest
    11·2 answers
  • Determine the scale factor for the following points: (4, 2) to (16, 8)
    15·1 answer
  • You borrow $25,000 to buy a boat. The simple interest rate is 4%. You pay the loan off after 10 years. What is the total amount
    14·1 answer
  • How much is 2 ÷ 247​
    13·1 answer
  • I will give u brainliest
    12·1 answer
  • The slope is also know as the? <br> over the?
    10·1 answer
  • PLS HELP!!! Pleaseee
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!