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never [62]
3 years ago
6

A school baseball team raised $810 for new uniforms. Each player on the team sold one book of tickets. There were 10 tickets and

each tickey cost $3. How many tickets were sold? What extra information in the problem is NOT needed?
Mathematics
1 answer:
Lena [83]3 years ago
3 0

Answer:

  • 270 tickets were sold
  • not needed: books per player, tickets per book

Step-by-step explanation:

To find the number of tickets sold, the total revenue needs to be divided by the revenue per ticket:

  (total revenue)/(revenue/ticket) = total tickets

  $810/$3 = 270 . . . total tickets

__

None of the other numbers in the problem are needed: books per player (1), tickets per book (10).

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que cantidad de ingereses genera un prestamo de 10000 dolares que se contrato el 1 de agosto de 2017 para reembolsarse el 1 de a
egoroff_w [7]

Answer:

que cantidad de ingereses genera un prestamo de 10000 dolares que se contrato el 1 de agosto de 2017 para reembolsarse el 1 de agosto de 2020, con interes simple del 10 % anua

6 0
3 years ago
Let f(x) represent a function.
STatiana [176]

Answer:

For f(x+\frac{5}{4}), f(x) is translated \frac{5}{4} units left.

For f(x)-\frac{5}{4}, f(x) is translated \frac{5}{4} units down.

Step-by-step explanation:

The transformation of f(x)\rightarrow f(x+C) means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of f(x)\rightarrow f(x)+C means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0, so, the function translates left by \frac{5}{4} units.

Similarly, in the transformation of f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}, so, the function translates down by \frac{5}{4} units.

3 0
3 years ago
Answer this for me pleasee i need help
Fiesta28 [93]

Answer:

x = 5 and x = -3

Step-by-step explanation:

hope it helps

7 0
4 years ago
Help please!!!
KatRina [158]
Corresponding angle
6 0
3 years ago
Which additional information could be used to prove that the triangles are congruent using AAS or ASA? Check all that apply.
Ad libitum [116K]

Consider the given triangles.

Given: \angle C \cong \angle Q

ASA congruence criterion states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

AAS congruence criterion states that if two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Consider the first part:

1. In triangles ABC and QPT

If we take \angle B \cong \angle P , BC \cong PQ along with the given condition.

Then the triangles are congruent by ASA congruence criterion.

2. If we take \angle A \cong \angle T and AC= TQ=3.2 along with the given condition.

Then the triangles are congruent by ASA congruence criterion.

3. As,\angle C \cong \angle Q, \angle A \cong \angle T and \angle B \cong \angle P, so the triangles can not be congruent.

4. If we take \angle A \cong \angle T and BC \cong PQ along with the given condition.

Then the triangles are congruent by AAS congruence criterion.

5. If we take AC=TQ=3.2 and CB=QP=3.2 along with the given condition, then the triangles are congruent but by SAS congruence criteria neither by ASA nor AAS congruence criterion.

7 0
3 years ago
Read 2 more answers
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