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blsea [12.9K]
3 years ago
12

7, 14, 21, 28 are the first 4 multiples of 7. What are the next 2 multiples?

Mathematics
2 answers:
Simora [160]3 years ago
7 0

Answer:

35 and 42

Step-by-step explanation:

7×2=14

7×3=21

7×4=28

7×5=35

7×6=42

Hope this helps!

dybincka [34]3 years ago
4 0

Answer: 35 then 42

Step-by-step explanation:

7=7*1

14=7*2

21=7*3

28=7*4

Next 2:

35=7*5

42=7*6

You might be interested in
The equation of a circle is (x + 3)2 + (y – 5)2 = 81. Determine the coordinates of the center of the circle and the length of th
Nataly_w [17]

Answer:

The center of the circle is (-3 , 5) and the length of the radius is 9 units

Step-by-step explanation:

* Lets revise the standard form of the equation of the circle

- The center-radius form of the circle equation is in the format

 (x – h)² + (y – k)² = r², where the center is the point (h, k) and

 the radius is r.

- This form of the equation is helpful, because you can easily find

  the center and the radius.

* Now lets solve the problem

- The equation is (x + 3)² + (y - 5)² = 81

- By comparing the two equations

∵  (x – h)² + (y – k)² = r² and  (x + 3)² + (y - 5)² = 81

# x - h = x + 3

∴ -h = 3 ⇒ divide both sides by -1

∴ h = -3

# y - k = y - 5

∴ k = 5

# h and k are the coordinates of the center of the circle

∴ The center of the circle is (-3 , 5)

# r² = 81 ⇒ take √ for both sides

∴ r = 9

∴ The length of the radius = 9 units

* The center of the circle is (-3 , 5) and the length of the radius is 9 units

3 0
3 years ago
The histogram below shows the heights, rounded to the nearest inch, of the members of the Oak High School basketball team. A. 1
Elan Coil [88]

Answer:

Range of player's height = 9 inch

Step-by-step explanation:

Given:

Number of players    Height range

4                                     66-67

8                                     68 -69

14                                    70-71

9                                     72-73

1                                      74-75

Find:

Range of player's height

Computation:

Range = Maximum value - Minimum Value

Range of player's height = Maximum height of a player - height of a player

Range of player's height = 75 inch - 66 inch

Range of player's height = 9 inch

5 0
2 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
2 years ago
96 divided by 6 distributive property of multuiplication
ololo11 [35]

Do 96 divided by 6.

6 goes into 96 16 times. therefore, your answer is 16

6 0
3 years ago
Describe the vector as an ordered pair around coordinates to the nearest 10th the diagram is not drawn to scale
xxMikexx [17]

Answer:

see explanation

Step-by-step explanation:

x = r cosΘ

y = r sinΘ

with r = 54 and Θ = 69°, thus

x = 54cos69° ≈ 19.4

y = 54sin69° ≈ 50.4

Thus (54, 69° ) as an ordered pair

= \left[\begin{array}{ccc}19.4\\50.4\\\end{array}\right]

4 0
2 years ago
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