The coordinates G(7, 3), H(9, 0), I(5, -1) form what type of polygon?

What is 30=12m I need help

Law Incorporation [45]

30=12m
you divide both sides by 12
so 30/12 is 2.5

8 0

4 years ago

Find a Cartesian equation for the curve.

Galina-37 [17]

$r = 3sec( \alpha ) \\ r = \frac{3}{cos( \alpha )}$

$x = rcos( \alpha ) \: \: \: \: \: \: \: cos( \alpha ) = \frac{x}{r}$

$r = \frac{3}{ \frac{x}{r} } \\ r = \frac{3r}{x} \: \: \: \: \: \: x = 3 \\ line$

6 0

2 years ago

ANSWER ASAP 23 POINTS

BARSIC [14]

He slings the stone at him

5 0

3 years ago

Read 2 more answers

What formula is used to show lines are parallel<br>to one another?

larisa86 [58]

Answer:

To figure out if 2 lines are parallel, compare their slopes. You can find the slope of a line by picking 2 points with XY coordinates, then put those coordinates into the formula Y2 minus Y1 divided by X2 minus X1. Calculate the slope of both lines. If they are the same, then the lines are parallel.

Step-by-step explanation:

To figure out if 2 lines are parallel, compare their slopes. You can find the slope of a line by picking 2 points with XY coordinates, then put those coordinates into the formula Y2 minus Y1 divided by X2 minus X1. Calculate the slope of both lines. If they are the same, then the lines are parallel.

3 0

3 years ago

Read 2 more answers

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

6 0

3 years ago