Answer:
Polymorphism
Explanation:
You can have a basic button class that gets inherited by other classes.
class Button {
function pushButton(){}
}
class ElevatorButton extends Button{};
class BigRedButton extends Button{};
With these new classes, they inherit from the basic button class. They can decide what happens when the method pushButton() is called.
You don't need to worry about what pushButton() actually does, you can just call it if the object is of the type "Button" and you can expect it to work.
Answer:
True
Explanation:
When open punctuation is used, we do not expect the use of punctuation after salutation or complimentary close. It is a relatively new concept in business writing and we can rightly use this method in modified block letter style of writing.
Some companies have developed business letter templates that are arranged in an open style, which permits the use of open punctuation in all aspect of business writings.
Answer:
Please see below
Explanation:
Suppose N = 10. And you have these dots equidistant from each other, and probability = 0.3. According to the data provided in the question statement, we will then have forty-five pairs of points. The task is to draw lines amongst these pairs, all 45 of them, with a 30% probability. Keep in mind that every one of the 45 lines are independent.
A few lines of simple code (just some for loops) needed to run this is attached in the image herewith, .
Answer:
Explanation:
The following code is written in Java. The function takes in the random object and creates a random number where it generates a random number and prints out the * characters, if the random number and the input num are the same it prints out both values and ends the function.
import java.util.Random;
class Brainly {
public static void main(String[] args) {
Random r = new Random();
randomStar(r, 12);
System.out.println();
randomStar(r, 19);
}
public static void randomStar(Random r, int num) {
while (true) {
int randomNum = r.nextInt(19) + 5;
if (randomNum != num) {
for (int x = 0; x < randomNum; x++) {
System.out.print("*");
}
System.out.print("\n");
} else {
for (int x = 0; x < randomNum; x++) {
System.out.print("*");
}
System.out.print("\n");
System.out.println("Random Number: " + randomNum);
System.out.println("Input Number: " + num);
break;
}
}
}
}
Answer:
B
Explanation:
Your computer may not have a pre-installed audio input driver or driver corrsponding to said device