Answer:
The answer to this question is given below in the explanation section.
Explanation:
When you use an array in the program, it occupies the memory where to store the data. However, it is noted that the other array cannot store the variable value where the first array has to store its variable value.
however, when you reassign the value their index position of the array, the values are reassigned. But it also depends on the CPU, because sometimes when you release the memory from the array, maybe some other programs get to occupy that location where the first array values were stored.
However, In Java, it is possible that the same int/integer comes at the same spot of the existing integer in an array, then the value at that particular index is reassigned.
Answer:
It focuses on one task and has no self awareness
Answer:
encrypted
Explanation:
to prevent others from viewing it
Answer:
subset([],[]).
subset([X|L],[X|S]) :-
subset(L,S).
subset(L, [_|S]) :-
subset(L,S).
Success:
subset([1,3], [1,2,3]).
subset(X, [1,3,4]). % error handling to compare sets in a given order
Fail:
subset([2,1], [1,2,3]). % compares in a different order from the first.
Explanation:
The function "Subset" in the source code above accepts two sets, then checks if the first set is a subset of the second. The code returns true if the condition is met.
The answer is D. The SUM function lets you add all the values along the specified cells. To use the SUM function, you type the equal symbol and the word "sum" then a parenthesis. Inside the parenthesis are the cells you want to add-up. Specify it from the first cell to the last. Add a colon in between to two cell locations. So the right formula to input in finding the sum of all the values from A1 to A10 is =sum(A1:A10).
