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3 years ago

I need help with this problem if anyone can help me.

Mathematics

1 answer:

nika2105 [10]3 years ago

6 0

You do 7 times 2 in parentheses and then minus that by 6-4 in parentheses so it will look like this , (7times2) - (6-4) = 12

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The coordinate point F(-8, 0) after a dilation with scale factor of 0.25, centered at the origin, becomes the point

FrozenT [24]

Answer:

$(-2,\, 0)$ .

Step-by-step explanation:

Dilate a point $(x,\, y)$ by a scale factor of $r$ with $(a,\, b)$ as the center, and the resultant point would be at $(a + r\, (x - a),\, b + r\, (y - a))$ .

In this question:

Point to dilate: $(x,\, y) = (-8,\, 0)$ .

Scale factor: $r = 0.25$ .

Center of dilation: $(a,\, b) = (0,\, 0)$ .

The resultant point would be:

$(0 + 0.25\, (-8 - 0),\, 0 + 0.25\, (0 - 0))$ , which simplifies to $(-2,\, 0)$ .

5 0

3 years ago

28 lunch; 15 % tip I need to show my workkkk

NeX [460]

28 x .15 = 4.2

28 + 4.2 = 32.2 <---- ANSWER

Hope this helps :)

5 0

4 years ago

Read 2 more answers

What is the answer to -3a=15

Butoxors [25]

Answer:

-5

Step-by-step explanation:

-3*-5=15

7 0

3 years ago

Read 2 more answers

How do you re-write this using only positive exponents? 3x^-4/3 (1+2x^5/3)

Kay [80]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\\\
and\qquad \quad a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
$

$\bf \cfrac{3x^{-\frac{4}{3}}}{3(1+2x^{\frac{5}{3}})}\implies \cfrac{3}{3}\cdot \cfrac{1}{x^{\frac{4}{3}}}\cdot \cfrac{1}{(1+2x^{\frac{5}{3}})}\implies \cfrac{1}{x^{\frac{4}{3}}(1+2x^{\frac{5}{3}})}$

$\bf \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}}x^{\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}+\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}2x^{\frac{9}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^3}
\\\\\\
\cfrac{1}{\sqrt[3]{x^4}+2x^3}\implies \cfrac{1}{x\sqrt[3]{x}+2x^3}\implies \cfrac{1}{x(\sqrt[3]{x}+2x^2)}$

8 0

4 years ago

37% of women consider themselves fans of professional baseball. you randomly select six women and ask each if she considers hers

valina [46]

Answer:

(a) 2.22

(b) 1.3986

Step-by-step explanation:

Let X denote the number of women who consider themselves fans of professional baseball.

The proportion of women who consider themselves fans of professional baseball is, p = 0.37.

A random sample of n = 6 women are selected and each was asked if she considers herself a fan of professional baseball.

Each woman's reply is independent of the others.

The random variable X thus follows a binomial distribution with parameters n = 6 and p = 0.37.

(a)

Compute the mean of the binomial distribution as follows:

$\text{Mean}=np=6\times 0.37=2.22$

(b)

Compute the variance of the binomial distribution as follows:

$\text{Variance}=np(1-p)=6\times 0.37\times (1-0.37)=1.3986$

(c)

Compute the standard deviation of the binomial distribution as follows:

$\text{Standard Deviation}=\sqrt{np(1-p)}=\sqrt{6\times 0.37\times (1-0.37)}=1.183$

5 0

3 years ago