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Snowcat [4.5K]
3 years ago
6

Katherine and Amy are members of the same sorority at college and are members of the school's swim team. They have been trying t

o master a difficult dive from the high board at the college's swimming pool. Amy is showing faster improvement in the dive than Katherine is. If they compare their performance as team mates and sorority sisters, social identity theory suggests that ________.A) Katherine should dislike Amy moreB) Amy should dislike Katherine moreC) Katherine should like Amy moreD) neither Katherine's nor Amy's liking for each other should changeE) Amy should like Katherine more
Biology
1 answer:
aniked [119]3 years ago
5 0

Answer:

Option (A).

Explanation:

Sociology may be defined as the subject that focus on the study of development and social interaction in society. Sociology is also known as the general science of the society.

Amy and Katherine are the member of same team and Amy shows fast development than Katherine. They both are competitor of each other. This is human behavior to jealous with the person that perform better than them. Here, the development of Amy makes jealous to Katherine and she starts disliking Amy.

Thus, the correct answer is option (A).

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3 years ago
When trying to evaluate whether a dog is showing strong aggression as opposed to strong fear, one can readily see the difference
gizmo_the_mogwai [7]
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6 0
2 years ago
In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t
Sergio [31]

Answer:

The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² +  2pq+ q²  = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = \sqrt{0.35} = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

8 0
3 years ago
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