Answer:
D
Step-by-step explanation:
For some side lengths to create a triangle, any two of the side lengths must have an added length together of less than the third leg. Otherwise, the vertices would simply not be able to be connected by the lines. In a), 3+5=8, but since it is not more, the triangle will not be able to be formed (it would basically just be a line.) In B, 7+8< 16. In C, there is the same situation as with the first example (4+15=19). Finally, in the last one, 5+7>12, and all of the side lengths work out. Therefore, the correct answer is D. Hope this helps!
Answer: Sally walked 3 minutes faster per mile
Hope it helped!
Answer:

Step-by-step explanation:
![\sf \frac{3}{a} x - 4 = 20\\\\Add \ 4 \ to \ both \ sides\\\\\frac{3}{a} x = 20+4\\\\\frac{3}{a} x = 24\\\\Multiply \ both \ sides \ by \ a\\\\3x = 24 * a\\\\Divide \ 3 \ to \ both \ sides\\\\x = 24a / 3\\\\x = 8a\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cfrac%7B3%7D%7Ba%7D%20x%20-%204%20%3D%2020%5C%5C%5C%5CAdd%20%5C%204%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Cfrac%7B3%7D%7Ba%7D%20x%20%3D%2020%2B4%5C%5C%5C%5C%5Cfrac%7B3%7D%7Ba%7D%20x%20%3D%2024%5C%5C%5C%5CMultiply%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%20a%5C%5C%5C%5C3x%20%3D%2024%20%2A%20a%5C%5C%5C%5CDivide%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cx%20%3D%2024a%20%2F%203%5C%5C%5C%5Cx%20%3D%208a%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
x<1
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable. Hope this helps!
Answer:
It is congruent to Angle A P C
Step-by-step explanation:
we know that
<u><em>Vertical angles</em></u> are the angles opposite each other when two lines cross. They are always congruent.
In this problem we have that
-----> by vertical angles
see the attached figure to better understand the problem
therefore
It is congruent to Angle A P C